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dynamic_programing/longest_common_subsequence/c++/longest_common_subsequence.cpp
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#include<iostream> | ||
#include<bits/stdc++.h> | ||
using namespace std; | ||
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int lpsH(string s, int start, int end, int **output){ | ||
if(start > end){ | ||
return 0; | ||
} | ||
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if(s.length() == 1 || start == end){ | ||
return 1; | ||
} | ||
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if(output[start][end] > -1){ | ||
return output[start][end]; | ||
} | ||
if(s[start] == s[end]){ | ||
output[start][end] = 2 + lpsH(s, start+1, end-1, output); | ||
return output[start][end]; | ||
} | ||
output[start][end] = max(lpsH(s, start+1, end, output), lpsH(s, start, end-1, output)); | ||
return output[start][end]; | ||
} | ||
int lcs(string s1, string s2){ | ||
int n1 = s1.length(); | ||
int **output = new int*[n1+1]; | ||
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for(int i = 0; i <= s1.length(); i++){ | ||
output[i] = new int[s2.length()+1]; | ||
for(int j = 0; j <= s2.length(); j++){ | ||
output[i][j] = -1; | ||
} | ||
} | ||
return lpsH(s1, 0, s1.length()-1, output); | ||
} | ||
int main{ | ||
string s1, s2; | ||
cin >> s1 >> s2; | ||
cout << lcs(s1, s2); | ||
} |