[이지민] - 항체 인식, 토마토, 우체국, 문자열 게임 2 #224
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soopeach
approved these changes
Mar 16, 2024
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| for i in range(26): | ||
| if len(alphabet[i]) >= k: | ||
| for j in range(0, len(alphabet[i]) - k + 1): | ||
| mini = min(mini, alphabet[i][j + k - 1] - alphabet[i][j] + 1) | ||
| maxi = max(maxi, alphabet[i][j + k - 1] - alphabet[i][j] + 1) |
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| for i in range(n): | ||
| if abs(people - (total - people - town[i][1])) < mini: | ||
| mini = abs(people - (total - people - town[i][1])) | ||
| result = town[i][0] | ||
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| people += town[i][1] |
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| for i in range(4): | ||
| if 0 <= nx + dx[i] < n and 0 <= ny + dy[i] < m: | ||
| if tomato[nx + dx[i]][ny + dy[i]] == 0: | ||
| queue.append([nx + dx[i], ny + dy[i]]) | ||
| tomato[nx + dx[i]][ny + dy[i]] = tomato[nx][ny] + 1 |
bngsh
approved these changes
Mar 16, 2024
| for i in range(len(w) - 1): | ||
| alphabet[ord(w[i]) - ord('a')].append(i) | ||
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| mini = 10_001 |
| mini = 1_000_000_000 * 100_000 | ||
| result = -1 | ||
| for i in range(n): | ||
| if abs(people - (total - people - town[i][1])) < mini: |
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저도 제 식이 뭔지 이해가 안갔었는데 지민님 설명 듣고 이해가 됐습니다 ㅎㅎ
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| if after[nx][ny] != update: | ||
| possible = -1 |
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헉..큐에 넣기 전에 before가 탐색중인 값인지도 조건에 추가하면 after가 다를때 바로 NO처리가 가능하군요...예외처리 댑악
jhg3410
approved these changes
Mar 16, 2024
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| if abs(people - (total - people - town[i][1])) < mini: | ||
| mini = abs(people - (total - people - town[i][1])) |
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| if result <= 1 : | ||
| print("YES") |
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resturn 된 possible 의 합으로 처리하는 부분이 좋았습니다
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📌 from issue #220 📌
📋문제 목록📋