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[장희직] - 작업, 키 순서, 구간 합 구하기 5, 도넛과 막대 그래프 #219

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54 changes: 54 additions & 0 deletions src/main/kotlin/heejik/53week/구간 합 구하기 5.kt
Original file line number Diff line number Diff line change
@@ -0,0 +1,54 @@
package heejik.`53week`

class `구간 합 구하기 5` {

private var n: Int = 0
private var m: Int = 0
private val board = mutableListOf<MutableList<Int>>()
private val poses = mutableListOf<List<Int>>()
fun solve() {
input()
changeBoard()
poses.forEach {
getPrefixSum(it[0] - 1, it[1] - 1, it[2] - 1, it[3] - 1).also { answer ->
println(answer)
}
}
}

private fun input() {
readln().split(' ').map { it.toInt() }.also {
n = it.first()
m = it.last()
}
repeat(n) {
board.add(readln().split(' ').map { it.toInt() }.toMutableList())
}
repeat(m) {
poses.add(readln().split(' ').map { it.toInt() })
}
}

private fun changeBoard() {
for (x in 0 until n) {
for (y in 0 until n) {
val minusX = if (x == 0) -1 else x - 1
val minusY = if (y == 0) -1 else y - 1
board[x][y] += (if (minusY != -1) board[x][minusY] else 0) +
(if (minusX != -1) board[minusX][y] else 0) -
(if (minusX != -1 && minusY != -1) board[minusX][minusY] else 0)
}
}
}

private fun getPrefixSum(x1: Int, y1: Int, x2: Int, y2: Int): Int {
val leftSum = if (y1 == 0) 0 else board[x2][y1 - 1]
val upSum = if (x1 == 0) 0 else board[x1 - 1][y2]
val diagonalSum = if (x1 == 0 || y1 == 0) 0 else board[x1 - 1][y1 - 1]
return board[x2][y2] - leftSum - upSum + diagonalSum
}
Comment on lines +44 to +49
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오 그래도 변수명을 잘지으셔서 이해가 잘 됩니다!

}

fun main() {
`구간 합 구하기 5`().solve()
}
46 changes: 46 additions & 0 deletions src/main/kotlin/heejik/53week/서강그라운드.kt
Original file line number Diff line number Diff line change
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package heejik.`53week`

import kotlin.math.max

class 서강그라운드 {

fun solve() {
val (n, m, r) = readln().split(' ').map { it.toInt() }
val itemCounts = readln().split(' ').map { it.toInt() }.toMutableList()
itemCounts.add(0, 0)
val distances = List(size = n + 1) { MutableList(size = n + 1) { 16 } }
var answer = 0

repeat(r) {
val (a, b, distance) = readln().split(' ').map { it.toInt() }
distances[a][b] = distance
distances[b][a] = distance
}

for (k in 1..n) {
for (i in 1..n) {
for (j in 1..n) {
if (distances[i][j] > distances[i][k] + distances[k][j]) {
distances[i][j] = distances[i][k] + distances[k][j]
}
}
}
}

for (region in 1..n) {
var sum = itemCounts[region]
for (other in 1..n) {
if (region == other) continue
if (distances[region][other] <= m) sum += itemCounts[other]
}
answer = max(answer, sum)
}

println(answer)
}
}


fun main() {
서강그라운드().solve()
}
52 changes: 52 additions & 0 deletions src/main/kotlin/heejik/53week/작업.kt
Original file line number Diff line number Diff line change
@@ -0,0 +1,52 @@
package heejik.`53week`

class 작업 {

private var n = 0
private var m = 0
private var findNum = 0
private var answer = 0

// 내부엔 나를 쏘는 애들
private lateinit var relation: List<MutableList<Int>>

fun solve() {
input()
bfs()
println(answer)
}

private fun input() {
readln().split(' ').map { it.toInt() }.also {
n = it[0]
m = it[1]
}
relation = List(size = n + 1) { emptyList<Int>().toMutableList() }
repeat(m) {
val (shot, receive) = readln().split(' ').map { it.toInt() }
relation[receive].add(shot)
}
findNum = readln().toInt()
}

private fun bfs() {
val deque = ArrayDeque<Int>()
val visited = BooleanArray(size = n + 1)
deque.add(findNum)
visited[findNum] = true

while (deque.isNotEmpty()) {
val standard = deque.removeFirst()
relation[standard].forEach {
if (visited[it]) return@forEach
deque.add(it)
visited[it] = true
answer++
}
}
}
}

fun main() {
작업().solve()
}
63 changes: 63 additions & 0 deletions src/main/kotlin/heejik/53week/키 순서.kt
Original file line number Diff line number Diff line change
@@ -0,0 +1,63 @@
package heejik.`53week`

import java.io.BufferedReader
import java.io.InputStreamReader

class `키 순서` {

private var n = 0
private var m = 0
private lateinit var relation: List<BooleanArray>

val br = BufferedReader(InputStreamReader(System.`in`))

fun solve() {
input()
createRelation()
getAnswer().also { answer ->
println(answer)
}
}

private fun input() {
br.readLine().split(' ').map { it.toInt() }.run {
n = this[0]
m = this[1]
}
relation = List(size = n + 1) { BooleanArray(size = n + 1) }

repeat(m) {
val (small, large) = br.readLine().split(' ').map { it.toInt() }
relation[small][large] = true
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한 방향으로만 해도 되는군요,,,,,,

}
}

private fun createRelation() {
for (k in 1..n) {
for (i in 1..n) {
for (j in 1..n) {
if (relation[i][k] && relation[k][j])
relation[i][j] = true
}
}
}
}
Comment on lines +35 to +44
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플루이드 워셜 엄청난 친구네요

Comment on lines +35 to +44
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플로이드 워셜로 구할 수도 있군요,,,!


private fun getAnswer(): Int {
var answer = 0
for (i in 1..n) {
var count = 0
for (j in 1..n) {
if (relation[i][j] || relation[j][i]) count++
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이렇게 체크하면 되는군요 👍

}
if (count == n - 1) answer++
}

return answer
}
}


fun main() {
`키 순서`().solve()
}