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[소병희] 표현 가능한 이진트리, 절댓값 힙, 치즈, 치킨 배달 #112

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Mar 12, 2023
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28 changes: 28 additions & 0 deletions src/main/kotlin/byeonghee/week26/절댓값 힙.kt
Original file line number Diff line number Diff line change
@@ -0,0 +1,28 @@
package byeonghee.week26

import java.io.*
import java.util.PriorityQueue
import kotlin.math.abs

class 소병희_절댓값힙 {

companion object {
fun solve(): Unit = with(BufferedReader(InputStreamReader(System.`in`))) {
val n = readLine().toInt()
val pq = PriorityQueue<Int> { a, b -> if (a + b == 0) a - b else abs(a) - abs(b) }
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pq를 굉장히 아름답게 쓰시네요,, 항상 배우고 갑니당


var x : Int
repeat(n) {
x = readLine().toInt()
when(x) {
0 -> println(pq.poll() ?: "0")
else -> pq.add(x)
}
}
}
}
}

fun main() {
소병희_절댓값힙.solve()
}
76 changes: 76 additions & 0 deletions src/main/kotlin/byeonghee/week26/치즈.kt
Original file line number Diff line number Diff line change
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package byeonghee.week26

import java.io.StreamTokenizer

class 소병희_치즈 {

companion object {
const val AIR = 0
const val CHEESE = 1

val dr = arrayOf(1, 0, -1, 0)
val dc = arrayOf(0, 1, 0, -1)

fun solve() = StreamTokenizer(System.`in`.bufferedReader()).run {

fun input() : Int {
nextToken()
return nval.toInt()
}

val h = input()
val w = input()
val plane = Array(h) { IntArray(w) }

val q = ArrayList<Pair<Int, Int>>()
var cheese = 0
var record = 0
var timeCost = 0

for(r in 0 until h) for(c in 0 until w) {
plane[r][c] = input()
if (plane[r][c] == CHEESE) cheese++
}

var r = 0
var c = 0
var nr = 0
var nc = 0
while(cheese > 0) {
val visited = Array(h) { BooleanArray(w) }
record = cheese
q.add(Pair(0, 0))
visited[0][0] = true

while(q.isNotEmpty()) {
q.removeFirst().let {
r = it.first
c = it.second
}

for(d in 0 until 4) {
nr = r + dr[d]
nc = c + dc[d]

if (nr !in 0 until h || nc !in 0 until w) continue
if (visited[nr][nc]) continue

if (plane[nr][nc] == CHEESE) {
plane[nr][nc] = AIR
cheese--
}
else q.add(Pair(nr, nc))
visited[nr][nc] = true
}
}
timeCost++
}

println("$timeCost\n$record")
}
}
}

fun main() {
소병희_치즈.solve()
}
68 changes: 68 additions & 0 deletions src/main/kotlin/byeonghee/week26/치킨 배달.kt
Original file line number Diff line number Diff line change
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package byeonghee.week26

import java.io.StreamTokenizer
import kotlin.math.abs

class 소병희_치킨배달 {

companion object {
fun solve() = StreamTokenizer(System.`in`.bufferedReader()).run {

fun input() : Int {
nextToken()
return nval.toInt()
}

val n = input()
val m = input()
val house = mutableListOf<Pair<Int, Int>>()
val franchise = mutableListOf<Pair<Int, Int>>()
var cityDist = Integer.MAX_VALUE
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Int의 상수 대신 Interger의 상수를 사용하신 이유가 있으신가요??

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ㅇㅁㅇ 아뇨 자바랑 헷갈렸나봐요 ㅋㅋㅋㅋㅋㅋㅋㅋㅋㅋㅋㅋㅋㅋㅋ


for(r in 0 until n) for(c in 0 until n) {
when(input()) {
1 -> house.add(Pair(r, c))
2 -> franchise.add(Pair(r, c))
}
}

val houseCnt = house.size
val franchiseCnt = franchise.size
val distMap = Array(houseCnt) { h -> IntArray(franchiseCnt) { f -> house[h].calcDist(franchise[f]) } }
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거리를 미리 저장하시다니!👍


fun checkCityDist(chickenDist: IntArray) {
var ret = 0
for(h in 0 until houseCnt) {
ret += chickenDist[h]
}
cityDist = cityDist.coerceAtMost(ret)
}

fun calcNewDist(f: Int, oldDist: IntArray) : IntArray {
return IntArray(houseCnt) { h -> oldDist[h].coerceAtMost(distMap[h][f]) }
}

fun makeM(f: Int, i: Int, chickenDist: IntArray) {
if (f == franchiseCnt && i < m) return
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조건처리가 좋은 것 같습니다..!!!

if (i == m) {
checkCityDist(chickenDist)
return
}

makeM(f + 1, i + 1, calcNewDist(f, chickenDist))
if(franchiseCnt - f >= m - i) makeM(f + 1, i, chickenDist)
}

makeM(0, 0, IntArray(houseCnt) { n * n })
print(cityDist)
}

fun Pair<Int, Int>.calcDist(p: Pair<Int, Int>) : Int {
return abs(first - p.first) + abs(second - p.second)
}
}
}

fun main() {
소병희_치킨배달.solve()
}
43 changes: 43 additions & 0 deletions src/main/kotlin/byeonghee/week26/표현 가능한 이진트리.kt
Original file line number Diff line number Diff line change
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package byeonghee.week26

class `소병희_표현 가능한 이진트리` {

val sb = StringBuilder()

fun solution(numbers: LongArray): IntArray {
var answer: IntArray = IntArray(numbers.size)

var trimmedSize = 0
var perfectSize = 0

for(i in numbers.indices) {
sb.clear()
sb.append(java.lang.Long.toBinaryString(numbers[i]))
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Long도 toBinaryString이 있군요...


trimmedSize = sb.length
perfectSize = getTreeSize(trimmedSize)
sb.insert(0, "0".repeat(perfectSize - trimmedSize))
answer[i] = checkSubTree(0, perfectSize - 1, 1)
}

return answer
}

fun getTreeSize(len: Int) : Int {
var ret = 1
while(ret <= len) {
ret *= 2
}
return ret - 1
}

fun checkSubTree(s: Int, e: Int, parent: Int) : Int {
val mid = (s + e) / 2
val root = sb[mid] - '0'
if (root == 1 && parent == 0) return 0
if (s == e) return 1

if (checkSubTree(s, mid - 1, root) == 0) return 0
return checkSubTree(mid + 1, e, root)
}
Comment on lines +34 to +42
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재귀 장인이시군요

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인졍..!

}