[이지민] 로봇 청소기, 보물섬, 센서, 합분해 #100
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bngsh
approved these changes
Feb 19, 2023
| fun dfs(x: Int, y: Int, d: Int) { | ||
| rooms[x][y] = -1 | ||
| var direction = -1 | ||
| for (i in 3 downTo 0) { |
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| val subQueue = mutableListOf<Pair<Int, Int>>() | ||
| queue.forEach{ num -> | ||
| for (i in 0 until 4) { | ||
| if(map[num.first + dx[i]][num.second + dy[i]] == "L") { | ||
| subQueue.add(Pair(num.first + dx[i], num.second + dy[i])) | ||
| map[num.first + dx[i]][num.second + dy[i]] = "W" | ||
| } | ||
| } | ||
| } | ||
| queue.clear() | ||
| queue = subQueue.toMutableList() | ||
| subQueue.clear() | ||
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| sum += 1 |
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풀이가 직관적으로 이해가 딱 됐습니다!! 구현력 대박입니다 이렇게 하면 L을 W으로 바꿔주면서 탐색해도 되는군여
soopeach
reviewed
Feb 19, 2023
| println(result) | ||
| } | ||
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| fun dfs(x: Int, y: Int, d: Int) { |
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| queue.forEach{ num -> | ||
| for (i in 0 until 4) { | ||
| if(map[num.first + dx[i]][num.second + dy[i]] == "L") { | ||
| subQueue.add(Pair(num.first + dx[i], num.second + dy[i])) | ||
| map[num.first + dx[i]][num.second + dy[i]] = "W" | ||
| } | ||
| } | ||
| } | ||
| queue.clear() |
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pop으로 forEach와 clear를 묶을 수 있지 않을까요??(queue)
soopeach
approved these changes
Feb 19, 2023
jhg3410
approved these changes
Feb 19, 2023
| map[x][y] = "W" | ||
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| while(queue.isNotEmpty()) { | ||
| val subQueue = mutableListOf<Pair<Int, Int>>() |
| println(result) | ||
| } | ||
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| fun dfs(x: Int, y: Int, d: Int) { |
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📌 from issue #96 📌
📋문제 목록📋