Done

programming_languages.rb

@@ -1,3 +1,53 @@
+
+#def reformat_languages(languages)
+#  new_hash = {}
+#  languages.each do |styles, langs|
+#    langs.each do |type, val|
+#      new_hash[type] ||= val
+#      new_hash[type][:style] ||= []
+#      new_hash[type][:style] << style
+#    end
+#  end
+#  new_hash
+#end
+
+#def reformat_languages(languages)
+#  new_hash = {}
+#    languages.each do |styles, langs|
+#      langs.each do |type, val|
+#        if new_hash.key?(type)
+#          new_hash[type][:style] << style
+#        else
+#          new_hash[type] = {:type => val.values[0], :style => [style]}
+#        end
+#     end
+#  end
+#new_hash
+#end
+
+# I'm really having a hard time with this lab.
+# I see there are two possible approaches to solving this lab. Both must account for
+# "Javascript" having two styles. I adopted the code from other student labs to study
+# while I develop a better understanding of these concepts.
+# The top approach uses the "Or Equals" evaluation to
+# construct the nested hashes, creating them if they are not already populated.
+# The second method uses if/else logic to determine the same thing.
+# In a third approach, the below method re-iterates over the hash to populate the
+# :style symbol.  I still do not quite understand the need for successive iterations or
+# if/else logic here; I know the top method will not pass without the Or Equals evaluation...
+
 def reformat_languages(languages)
-  # your code here
-end
+  new_hash = {}
+  languages.each do |styles, langs|
+    langs.each do |type, val|
+      new_hash[type] = val
+      new_hash[type][:style] = []
+    end
+  end
+  languages.each do |styles, langs|
+    langs.each do |type, val|
+      new_hash[type][:style] << styles
+    end
+  end
+  return new_hash
+ end