Lab subqueries.sql

subqueries.sql

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+USE sakila;
+SELECT 
+    COUNT(i.film_id) AS hunchback_count
+FROM
+    inventory i
+WHERE
+    i.film_id = (SELECT f.film_id
+        FROM
+            film f
+            WHERE f.title = 'Hunchback Impossible');
+
+SELECT DISTINCT(f.title)
+FROM film f
+WHERE
+	f.length > (SELECT AVG(length) FROM film);
+
+SELECT 
+    a.first_name, a.last_name
+FROM
+    actor a
+WHERE
+    a.actor_id IN (SELECT 
+            film_actor.actor_id
+        FROM
+            film_actor
+        WHERE
+            film_actor.film_id = (SELECT 
+                    film.film_id
+                FROM
+                    film
+                WHERE
+                    film.title = 'Alone Trip'));
+
+SELECT 
+    f.title
+FROM
+    film f
+WHERE
+    f.film_id IN (SELECT 
+            fc.film_id
+        FROM
+            film_category fc
+        WHERE
+            fc.category_id = (SELECT 
+                    c.category_id
+                FROM
+                    category c
+                WHERE
+                    c.name = 'Family'));
+
+SELECT 
+    cu.first_name, cu.email
+FROM
+    customer cu
+        JOIN
+    store s ON cu.store_id = s.store_id
+WHERE
+    s.address_id IN (SELECT 
+            a.address_id
+        FROM
+            address a
+                JOIN
+            city ci ON a.city_id = ci.city_id
+                JOIN
+            country co ON ci.country_id = co.country_id
+        WHERE
+            co.country = 'Canada');
+
+SELECT ac.first_name, ac.last_name
+FROM actor ac
+WHERE ac.actor_id = (SELECT fa.actor_id FROM film_actor fa
+GROUP BY fa.actor_id
+ORDER BY Count(fa.film_id) DESC
+LIMIT 1);
+
+SELECT 
+    f.title
+FROM
+    film f
+        JOIN
+    inventory i ON f.film_id = i.film_id
+        JOIN
+    rental r ON i.inventory_id = r.inventory_id
+WHERE
+    r.customer_id = (SELECT 
+            p.customer_id
+        FROM
+            payment p
+        GROUP BY p.customer_id
+        ORDER BY SUM(p.amount) DESC
+        LIMIT 1);
+
+SELECT 
+    p.customer_id AS client_id,
+    SUM(p.amount) AS total_amount_spent
+FROM
+    payment p
+GROUP BY p.customer_id
+HAVING SUM(p.amount) > (SELECT 
+        AVG(total_spent)
+    FROM
+        (SELECT 
+            SUM(amount) AS total_spent
+        FROM
+            payment
+        GROUP BY customer_id) AS subquery)
+ORDER BY total_amount_spent DESC;