w4 lab5 done

lab5.sql

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+USE sakila;
+
+#1 Determine the number of copies of the film "Hunchback Impossible" that exist in the inventory system.
+
+SELECT COUNT(*)
+FROM inventory as inv
+INNER JOIN (SELECT title, film_id
+			FROM film
+            WHERE title = "Hunchback Impossible") as f
+ON inv.film_id = f.film_id;
+
+
+#2 List all films whose length is longer than the average length of all the films in the Sakila database.
+
+SELECT * 
+FROM film
+WHERE length > (SELECT AVG(length) FROM film);
+
+
+#3 Use a subquery to display all actors who appear in the film "Alone Trip".
+
+SELECT first_name, last_name
+FROM actor
+INNER JOIN film_actor
+ON actor.actor_id = film_actor.actor_id
+INNER JOIN (SELECT film_id
+			FROM film
+            WHERE title = "Alone Trip") as film
+ON film_actor.film_id = film.film_id;
+
+#4 Sales have been lagging among young families, and you want to target family movies for a promotion. Identify all movies categorized as family films.
+SELECT film.film_id, title, category_name
+FROM film
+INNER JOIN film_category as fc
+ON film.film_id = fc.film_id
+INNER JOIN (SELECT category_id, name as category_name
+			FROM category
+            WHERE name = "Family") as cat
+ON fc.category_id = cat.category_id;
+
+#5 Retrieve the name and email of customers from Canada using both subqueries and joins. To use joins, you will need to identify the relevant tables and their primary 
+# and foreign keys.
+
+SELECT c.first_name, c.last_name, c.email, country.country
+FROM customer c
+JOIN address a
+ON c.address_id = a.address_id
+JOIN city 
+ON a.city_id = city.city_id
+JOIN (SELECT country_id, country FROM country WHERE country = "Canada") country
+ON city.country_id = country.country_id;
+
+#6 Determine which films were starred by the most prolific actor in the Sakila database. A prolific actor is defined as the actor who has acted in the most number of films. 
+#First, you will need to find the most prolific actor and then use that actor_id to find the different films that he or she starred in.
+
+SELECT film.title 
+FROM film 
+JOIN film_actor ON film.film_id = film_actor.film_id 
+WHERE film_actor.actor_id = (
+    SELECT actor_id 
+    FROM (
+        SELECT actor_id, COUNT(film_id) AS films 
+        FROM film_actor 
+        GROUP BY actor_id 
+        ORDER BY films DESC 
+        LIMIT 1
+    ) AS subquery
+);
+
+#7 Find the films rented by the most profitable customer in the Sakila database. You can use the customer and payment tables to find the most profitable customer, i.e., 
+#the customer who has made the largest sum of payments.
+
+SELECT film.title 
+FROM film 
+JOIN inventory ON film.film_id = inventory.film_id 
+JOIN rental ON inventory.inventory_id = rental.inventory_id 
+JOIN payment ON rental.rental_id = payment.rental_id 
+WHERE payment.customer_id = (
+    SELECT customer_id 
+    FROM payment 
+    GROUP BY customer_id 
+    ORDER BY SUM(amount) DESC 
+    LIMIT 1
+);
+
+#8 Retrieve the client_id and the total_amount_spent of those clients who spent more than the average of the total_amount spent by each client. 
+#You can use subqueries to accomplish this.
+
+SELECT customer_id, SUM(amount) as total_amount_spent
+FROM payment
+GROUP BY customer_id
+HAVING total_amount_spent > (SELECT AVG(amount) FROM payment);