‘lab-sql-joins’

lab-sql-joins.sql

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+-- Challenge - Joining on multiple tables using the Sakila database:
+
+-- 1. List the number of films per category.
+
+SELECT 
+    c.name AS category_name,
+    COUNT(fc.film_id) AS number_of_films
+FROM
+    category c
+        JOIN
+    film_category fc ON c.category_id = fc.category_id
+GROUP BY category_name
+ORDER BY category_name;
+
+-- 2. Retrieve the store ID, city, and country for each store.
+
+SELECT 
+    s.store_id, 
+    c.city_id AS store_city, 
+    c.country_id AS store_country
+FROM
+    store s
+JOIN 
+    address a ON s.address_id = a.address_id
+JOIN 
+    city c ON a.city_id = c.city_id;
+
+-- 3. Calculate the total revenue generated by each store in dollars.
+
+SELECT 
+    s.store_id, SUM(p.amount) AS total_revenue
+FROM
+    payment p
+        JOIN
+    rental r ON p.rental_id = r.rental_id
+        JOIN
+    inventory i ON r.inventory_id = i.inventory_id
+        JOIN
+    store s ON i.store_id = s.store_id
+GROUP BY s.store_id;
+
+
+-- 4. Determine the average running time of films for each category.
+SELECT 
+    c.name, AVG(f.length) AS average_length
+FROM
+    category c
+        JOIN
+    film_category fc ON c.category_id = fc.category_id
+        JOIN
+    film f ON fc.film_id = f.film_id
+GROUP BY c.name;
+
+
+-- Bonus:
+-- 5. Identify the film categories with the longest average running time.
+
+SELECT 
+    c.name, AVG(f.length) AS average_length
+FROM
+    category c
+        JOIN
+    film_category fc ON c.category_id = fc.category_id
+        JOIN
+    film f ON fc.film_id = f.film_id
+GROUP BY c.name
+ORDER BY average_length DESC;
+
+-- 7. Determine if "Academy Dinosaur" can be rented from Store 1.
+
+SELECT 
+    f.title, i.store_id
+FROM
+    film f
+        JOIN
+    inventory i ON f.film_id = i.film_id
+        JOIN
+    store s ON i.store_id = s.store_id
+WHERE
+    f.title = 'Academy Dinosaur'
+        AND s.store_id = 1
+;
+
+SELECT 
+    f.title,
+    s.store_id,
+    COUNT(i.inventory_id) AS available_copies
+FROM
+    film f
+        JOIN
+    inventory i ON f.film_id = i.film_id
+        JOIN
+    store s ON i.store_id = s.store_id
+WHERE
+    f.title = 'Academy Dinosaur'
+        AND s.store_id = 1
+GROUP BY f.title , s.store_id;
+
+-- 8. Provide a list of all distinct film titles, along with their availability status in the inventory. Include a column indicating whether each title is 'Available' or 'NOT available.' 
+-- Note that there are 42 titles that are not in the inventory, and this information can be obtained using a CASE statement combined with IFNULL.
+
+SELECT 
+    f.title,
+    CASE
+        WHEN IFNULL(MAX(i.inventory_id), 0) = 0 THEN 'NOT available'
+        ELSE 'Available'
+    END AS availability
+FROM
+    film f
+        LEFT JOIN
+    inventory i ON f.film_id = i.film_id
+GROUP BY f.title;