Solved Lab v1

README.md

@@ -48,18 +48,103 @@ Write SQL queries to perform the following tasks using the Sakila database:
 
 
 1. List the number of films per category.
+
+SELECT c.name, count(fc.category_id) as num_films
+FROM film_category as fc
+JOIN category as c
+USING(category_id)
+GROUP BY c.name
+ORDER BY num_films DESC;
+
 2. Retrieve the store ID, city, and country for each store.
+
+SELECT s.store_id, ci.city, co.country
+from store as s
+JOIN address
+USING(address_id)
+JOIN city as ci
+USING(city_id)
+JOIN country as co
+USING (country_id);
+
 3.  Calculate the total revenue generated by each store in dollars.
+
+SELECT s.store_id, c.city, SUM(p.amount) as total_revenue
+from customer 
+JOIN store as s
+USING(store_id)
+JOIN payment as p
+USING(customer_id)
+JOIN address as a
+ON c.address_id = a.address_id
+JOIN city as c
+USING(city_id)
+GROUP BY s.store_id, c.city
+ORDER BY total_revenue DESC;
+
 4.  Determine the average running time of films for each category.
 
+SELECT c.name, ROUND(AVG(f.length)) as average_running_time
+FROM film as f
+JOIN film_category
+USING(film_id)
+JOIN category as c
+USING(category_id)
+GROUP BY c.name
+ORDER BY average_running_time DESC;
 
 **Bonus**:
 
 5.  Identify the film categories with the longest average running time.
+
+SELECT c.name, ROUND(AVG(f.length)) as average_running_time
+FROM film as f
+JOIN film_category
+USING(film_id)
+JOIN category as c
+USING(category_id)
+GROUP BY c.name
+ORDER BY average_running_time DESC
+LIMIT 2;
+
 6.  Display the top 10 most frequently rented movies in descending order.
+
+SELECT f.title, COUNT(r.rental_id) as num_rentals
+FROM rental as r
+JOIN inventory
+USING(inventory_id)
+JOIN film as f
+USING(film_id)
+GROUP BY f.title
+ORDER BY num_rentals DESC
+LIMIT 10;
+
 7. Determine if "Academy Dinosaur" can be rented from Store 1.
+
+SELECT store_id, title,
+  CASE 
+    WHEN COUNT(*) > 0 THEN 'YES' 
+    ELSE 'NO' 
+    END AS is_available
+FROM store
+JOIN inventory
+USING(store_id)
+JOIN film
+USING(film_id)
+WHERE store_id = 1 AND title='Academy Dinosaur';
+
 8. Provide a list of all distinct film titles, along with their availability status in the inventory. Include a column indicating whether each title is 'Available' or 'NOT available.' Note that there are 42 titles that are not in the inventory, and this information can be obtained using a `CASE` statement combined with `IFNULL`."
 
+SELECT DISTINCT(f.title),
+CASE
+WHEN IFNULL(i.inventory_id, 0) = 0 THEN 'NOT available'
+ELSE 'Available'
+END AS availability
+FROM film f
+LEFT JOIN inventory i
+USING (film_id)
+ORDER BY title;
+
 Here are some tips to help you successfully complete the lab:
 
 ***Tip 1***: This lab involves joins with multiple tables, which can be challenging. Take your time and follow the steps we discussed in class:

lab-sql-joins.sql

@@ -0,0 +1,131 @@
+USE sakila;
+
+
+-- 1. Enumere el número de películas por categoría.
+
+SELECT c.name AS categoria, COUNT(f.film_id) AS num_peliculas
+FROM category c
+JOIN film_category fc 
+ON c.category_id = fc.category_id
+JOIN film f 
+ON fc.film_id = f.film_id
+GROUP BY c.name
+ORDER BY num_peliculas DESC;
+
+
+SELECT c.name, count(fc.category_id) as num_films
+FROM film_category as fc
+JOIN category as c
+USING(category_id)
+GROUP BY c.name
+ORDER BY num_films DESC;
+
+
+-- 2. Recupere el ID de la tienda, la ciudad y el país de cada tienda.
+SELECT s.store_id, c.city, co.country
+FROM store s
+JOIN address a 
+ON s.address_id = a.address_id
+JOIN city c 
+ON a.city_id = c.city_id
+JOIN country co 
+ON c.country_id = co.country_id;
+
+
+SELECT s.store_id, ci.city, co.country
+FROM store as s
+JOIN address
+USING(address_id)
+JOIN city as ci
+USING(city_id)
+JOIN country as co
+USING (country_id);
+
+-- 3. Calcule los ingresos totales generados por cada tienda en dólares.
+
+SELECT s.store_id, c.city, SUM(p.amount) as total_revenue
+FROM customer as cu
+JOIN store as s
+USING(store_id)
+JOIN payment as p
+USING(customer_id)
+JOIN address as a
+ON s.address_id = a.address_id
+JOIN city as c
+USING(city_id)
+GROUP BY s.store_id, c.city
+ORDER BY total_revenue DESC;
+
+
+SELECT s.store_id, SUM(p.amount) as total_revenue
+FROM customer
+JOIN store as s
+USING(store_id)
+JOIN payment as p
+USING(customer_id)
+GROUP BY s.store_id
+ORDER BY total_revenue DESC;
+
+-- 4. Determinar el tiempo promedio de ejecución de las películas para cada categoría.
+
+SELECT c.name, ROUND(AVG(f.length)) as average_running_time
+FROM film as f
+JOIN film_category
+USING(film_id)
+JOIN category as c
+USING(category_id)
+GROUP BY c.name
+ORDER BY average_running_time DESC;
+
+-- 5. Identifique las categorías de películas con el tiempo de ejecución promedio más largo.
+
+SELECT c.name, ROUND(AVG(f.length)) as average_running_time
+FROM film as f
+JOIN film_category
+USING(film_id)
+JOIN category as c
+USING(category_id)
+GROUP BY c.name
+ORDER BY average_running_time DESC
+LIMIT 2;
+
+-- 6. Muestra las 10 películas más alquiladas en orden descendente.
+
+SELECT f.title, COUNT(r.rental_id) as num_rentals
+FROM rental as r
+JOIN inventory
+USING(inventory_id)
+JOIN film as f
+USING(film_id)
+GROUP BY f.title
+ORDER BY num_rentals DESC
+LIMIT 10;
+
+-- 7. Determinar si "Academy Dinosaur" se puede alquilar en la Tienda 1.
+
+SELECT store_id, title, 
+  CASE
+    WHEN COUNT(*) > 0 THEN 'YES'
+    ELSE 'NO'
+    END AS is_available
+FROM store
+JOIN inventory
+USING(store_id)
+JOIN film
+USING(film_id)
+WHERE store_id = 1 AND title='Academy Dinosaur';
+
+
+-- 8.  Proporcione una lista de todos los títulos de películas distintos, junto con su estado de disponibilidad en el inventario. 
+-- Incluya una columna que indique si cada título está "Disponible" o "NO disponible". 
+-- Tenga en cuenta que hay 42 títulos que no están en el inventario y esta información se puede obtener utilizando una CASEdeclaración combinada con IFNULL".
+
+SELECT DISTINCT(f.title),
+    CASE
+        WHEN IFNULL(i.inventory_id, 0) = 0 THEN 'NOT available'
+        ELSE 'Available'
+    END AS availability
+FROM film f
+LEFT JOIN inventory i
+USING (film_id)
+ORDER BY title;