Merge branch 'master' of github.com:UniMath/SymmetryBook

congp.tex

@@ -206,17 +206,20 @@ \section{The pullback}
 
 \begin{xca}
   Prove that if $f:\Hom(H,G)$ and $f':\Hom(H',G)$ are homomorphisms,
-  then the pointed version of \cref{xca:univpropofpullback} induces an equivalence
-  $$
-  \Hom(K,H)\times_{\Hom(K,G)}\Hom(K,H')\simeq \Hom(K,H\times_GH')
-  $$
-  for all groups $K$ and an equivalence
+  then the pointed version of \cref{xca:univpropofpullback} induces an
+  equivalence
+  \[
+    \Hom(K,H)\times_{\Hom(K,G)}\Hom(K,H')\simeq \Hom(K,H\times_GH')
+  \]
+  for all groups $K$ and an equivalence%
+  \stepcounter{footnote}\footnotetext{%
+    Hint: set $A\defequi \Sc$, $B\defequi \BH$, $C\defequi \BH'$ and $D\defequi \BG$.}%
+  \addtocounter{footnote}{-1}
   \[
     \USymH \times_{\USymG} \USymH'
     \simeq (\shape_{H\times_GH'}=\shape_{H\times_GH'}).\text{\footnotemark}
   \]
-  Elevate the last equivalence to a statement about abstract groups.\footnotetext{%
-    Hint: set $A\defequi \Sc$, $B\defequi \BH$, $C\defequi \BH'$ and $D\defequi \BG$.}
+  Elevate the last equivalence to a statement about abstract groups.
 \end{xca}
 
 \begin{remark}