completed js assignment 7

Assignment1/Q1_DeepCopyObject.js

@@ -0,0 +1,34 @@
+/*
+1.
+ How will you create a new copy of the object below while updating the value of address.details[0] to “5“?
+{
+ name:”Harry Potter”,
+ age: 12,
+ address: {
+  details: [“4”, “Privet Drive”],
+  area:”Little Whinging”,
+  city: “Surrey”,
+  state: “England”
+ } 
+}
+*/
+
+const person = {
+  name: "Harry Potter",
+  age: 12,
+  address: {
+    details: ["4", "Privet Drive"],
+    area: "Little Whinging",
+    city: "Surrey",
+    state: "England",
+  },
+};
+
+//Copying the object using structuredClone()
+
+const copiedPerson = JSON.parse(JSON.stringify(person));
+
+copiedPerson.address.details[0] = 5;
+
+console.log(person);
+console.log(copiedPerson);

Assignment1/Q2_filter_object.js

@@ -0,0 +1,51 @@
+/*
+2. Write a function filterObj that will filter out all the keys of a flat object that have objects or arrays using Object.keys and Object.entries. 
+Example:
+let obj = {
+ a:”Apple”,
+ b:[“Basketball”,”Baseball”],
+ c: {
+  call: “cellphone”
+ },
+ d: “Dog”
+}
+filterObject(obj) //This should return {a:”Apple”, d:”Dog”}
+*/
+
+let obj = {
+  a: "Apple",
+  b: ["Basketball", "Baseball"],
+  c: {
+    call: "cellphone",
+  },
+  d: "Dog",
+};
+
+let newObj = {};
+const filterObj = (obj) => {
+  Object.keys(obj).forEach((val) => {
+    if (typeof obj[val] !== "object" || obj[val] === null) {
+      newObj[val] = obj[val];
+    }
+  });
+  return newObj;
+};
+
+console.log(filterObj(obj));
+
+// const flattenObj = (obj) => {
+//   let flatObject = {};
+//   for (const idx in obj) {
+//     if (typeof obj[idx] === "object") {
+//       const temp = flattenObj(obj[idx]);
+//       for (const tempIdx in temp) {
+//         flatObject[idx + "." + tempIdx] = temp[tempIdx];
+//       }
+//     } else {
+//       flatObject[idx] = obj[idx];
+//     }
+//   }
+//   return flatObject;
+// };
+
+// console.log(flattenObj(obj));

Assignment2/Q1_MapBy_Object.js

@@ -0,0 +1,47 @@
+/*
+Write a function mapBy to convert an array of objects into an object mapped by the specified key:
+Example: 
+ Let users = [{
+"id": 1,
+"first_name": "Nicki",
+"email": "[email protected]",
+"date_of_birth": "2009/05/09"
+}, {
+"id": 2,
+"first_name": "Raychel",
+"email": "[email protected]",
+"date_of_birth": "1996/11/05"
+}];
+mapBy(users, “first_name”) 
+
+//This should return
+//{
+// “Nicki”:{id:1, first_name:”Nicki”, ...},
+// “Raychel”:{id:2, first_name:”Raychell”, ...},
+//}
+*/
+
+let users = [
+  {
+    id: 1,
+    first_name: "Nicki",
+    email: "[email protected]",
+    date_of_birth: "2009/05/09",
+  },
+  {
+    id: 2,
+    first_name: "Raychel",
+    email: "[email protected]",
+    date_of_birth: "1996/11/05",
+  },
+];
+
+const mapBy = (users, value) => {
+  const newObj = users.reduce((acc, curr) => {
+    acc[curr[value]] = curr;
+    return acc;
+  }, {});
+  return newObj;
+};
+
+console.log(mapBy(users, "first_name"));

Assignment2/Q2_GroupBy_Object.js

@@ -0,0 +1,105 @@
+/*
+Write a functiongroupBy to convert an array of objects into groups based on the specified key:
+ let users = [{
+"id": 1,
+"first_name": "Nicki",
+"email": "[email protected]",
+"date_of_birth": "2009/05/09",
+“gender”:”Male”,
+}, {
+"id": 2,
+"first_name": "Raychel",
+"email": "[email protected]",
+"date_of_birth": "1996/11/05",
+  “gender”:”Female”
+}, {
+"id": 3,
+"first_name": "Demetris",
+"email": "[email protected]",
+"date_of_birth": "2018/12/31",
+  “gender”:”Male”
+}, {
+"id": 4,
+"first_name": "Amata",
+"email": "[email protected]",
+"date_of_birth": "2012/05/23",
+  “gender”:”Female”
+}];
+groupBy(users, “gender”)
+//This should return 
+//{
+//“Male”:[
+// {id:1, first_name:”Nicki”, ...}, 
+// {id:3, first_name:”Demetris”, ...}
+//]
+//“Female”:[
+// {id: 2, first_name:”Raychel”, ...},
+// {id: 4, first_name:”Amata”, ...}
+//]
+//}
+
+*/
+
+let users = [
+  {
+    id: 1,
+    first_name: "Nicki",
+    email: "[email protected]",
+    date_of_birth: "2009/05/09",
+    gender: "Male",
+  },
+  {
+    id: 2,
+    first_name: "Raychel",
+    email: "[email protected]",
+    date_of_birth: "1996/11/05",
+    gender: "Female",
+  },
+  {
+    id: 3,
+    first_name: "Demetris",
+    email: "[email protected]",
+    date_of_birth: "2018/12/31",
+    gender: "Male",
+  },
+  {
+    id: 4,
+    first_name: "Amata",
+    email: "[email protected]",
+    date_of_birth: "2012/05/23",
+    gender: "Female",
+  },
+];
+
+// const groupBy = (users, value) => {
+//   let result = {};
+//   let maleArr = [];
+//   let femaleArr = [];
+//   users.map((user) => {
+//     if (user[value] === "Male") {
+//       maleArr.push(user);
+//     } else {
+//       femaleArr.push(user);
+//     }
+//   });
+
+//   result["Male"] = maleArr;
+//   result["Female"] = femaleArr;
+//   return result;
+// };
+
+// console.log(groupBy(users, "gender"));
+
+const groupBy = (users, key) => {
+  return users.reduce((acc, object) => {
+    const value = object[key];
+    if (acc[value]) {
+      acc[value].push(object);
+    } else {
+      acc[value] = [object];
+    }
+    return acc;
+  }, {});
+};
+
+console.log(groupBy(users, "gender"));

Assignment2/Q3_Sort_Object.js

@@ -0,0 +1,76 @@
+/*
+rite a function that sorts an array of objects by the key that is passed in the second argument, and in the order passed as the 3rd argiment. 
+Example:
+ let users = [{
+"id": 1,
+"first_name": "Nicki",
+"email": "[email protected]",
+"date_of_birth": "2009/05/09",
+“gender”:”Male”,
+}, {
+"id": 2,
+"first_name": "Raychel",
+"email": "[email protected]",
+"date_of_birth": "1996/11/05",
+  “gender”:”Female”
+}, {
+"id": 3,
+"first_name": "Demetris",
+"email": "[email protected]",
+"date_of_birth": "2018/12/31",
+  “gender”:”Male”
+}, {
+"id": 4,
+"first_name": "Amata",
+"email": "[email protected]",
+"date_of_birth": "2012/05/23",
+  “gender”:”Female”
+}]
+sort(users, “id”, “desc”) //Should return users sorted by id in descending order
+sort(users, “first_name “asc”) //Should return users sorted by first_name in ascending order
+
+*/
+
+let users = [
+  {
+    id: 1,
+    first_name: "Nicki",
+    email: "[email protected]",
+    date_of_birth: "2009/05/09",
+    gender: "Male",
+  },
+  {
+    id: 2,
+    first_name: "Raychel",
+    email: "[email protected]",
+    date_of_birth: "1996/11/05",
+    gender: "Female",
+  },
+  {
+    id: 3,
+    first_name: "Demetris",
+    email: "[email protected]",
+    date_of_birth: "2018/12/31",
+    gender: "Male",
+  },
+  {
+    id: 4,
+    first_name: "Amata",
+    email: "[email protected]",
+    date_of_birth: "2012/05/23",
+    gender: "Female",
+  },
+];
+
+const sort = (users, key, type) => {
+  users.sort((prev, next) => {
+    if (prev[key] > next[key]) return type === "asc" ? 1 : -1;
+    if (prev[key] < next[key]) return type === "asc" ? -1 : 1;
+    return 0;
+  });
+
+  return users;
+};
+
+console.log(sort(users, "id", "desc")); //Should return users sorted by id in descending order
+console.log(sort(users, "first_name", "asc")); //Should return users sorted by first_name in ascending order