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Proof of incompleteness theorem via derivability conditions #1
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have : Subtheory T₀ (T ∪ {~σ}) := by sorry; | ||
have : Derivability1 T₀ (T ∪ {~σ}) := by sorry; | ||
have : Derivability2 T₀ (T ∪ {~σ}) := by sorry; | ||
have : Derivability3 T₀ (T ∪ {~σ}) := by sorry; |
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明らかに導出可能性条件は保存されるはず
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PropositionalCalculusの部分はLogic.Logic.HilbertStyle
に移してもいいと思う
lemma existsKreiselSentence [hdef : Definable.Sigma T n] (σ) | ||
: ∃ (K : Sentence ℒₒᵣ), IsKrieselSentence T₀ T K σ := by sorry |
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Löbの定理を第2不完全性定理を用いずに示すためにこの補題が必要だが,代入に関する問題(Subsentenceの束縛されていない変数の数が合わない?)で上手く出来なかった記憶がある
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HilbertStyleの補題を使っている証明をhttps://github.com/iehality/lean4-logic/blob/master/Logic/AutoProver/Prover.lean の |
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