Add solution and test-cases for problem 2558

leetcode/2501-2600/2558.Take-Gifts-From-the-Richest-Pile/README.md

@@ -0,0 +1,42 @@
+# [2558.Take Gifts From the Richest Pile][title]
+
+## Description
+You are given an integer array `gifts` denoting the number of gifts in various piles. Every second, you do the following:
+
+- Choose the pile with the maximum number of gifts.
+- If there is more than one pile with the maximum number of gifts, choose any.
+- Leave behind the floor of the square root of the number of gifts in the pile. Take the rest of the gifts.
+
+Return the number of gifts remaining after `k` seconds.
+
+**Example 1:**
+
+```
+Input: gifts = [25,64,9,4,100], k = 4
+Output: 29
+Explanation: 
+The gifts are taken in the following way:
+- In the first second, the last pile is chosen and 10 gifts are left behind.
+- Then the second pile is chosen and 8 gifts are left behind.
+- After that the first pile is chosen and 5 gifts are left behind.
+- Finally, the last pile is chosen again and 3 gifts are left behind.
+The final remaining gifts are [5,8,9,4,3], so the total number of gifts remaining is 29.
+```
+
+**Example 2:**
+
+```
+Input: gifts = [1,1,1,1], k = 4
+Output: 4
+Explanation: 
+In this case, regardless which pile you choose, you have to leave behind 1 gift in each pile. 
+That is, you can't take any pile with you. 
+So, the total gifts remaining are 4.
+```
+
+## 结语
+
+如果你同我一样热爱数据结构、算法、LeetCode，可以关注我 GitHub 上的 LeetCode 题解：[awesome-golang-algorithm][me]
+
+[title]: https://leetcode.com/problems/take-gifts-from-the-richest-pile
+[me]: https://github.com/kylesliu/awesome-golang-algorithm

leetcode/2501-2600/2558.Take-Gifts-From-the-Richest-Pile/Solution.go

@@ -1,5 +1,60 @@
 package Solution
 
-func Solution(x bool) bool {
+import "container/heap"
+
+type heap2558 []int
+
+func (h *heap2558) Len() int {
+	return len(*h)
+}
+
+func (h *heap2558) Swap(i, j int) {
+	(*h)[i], (*h)[j] = (*h)[j], (*h)[i]
+}
+
+func (h *heap2558) Less(i, j int) bool {
+	return (*h)[i] > (*h)[j]
+}
+
+func (h *heap2558) Push(x any) {
+	*h = append(*h, x.(int))
+}
+
+func (h *heap2558) Pop() any {
+	old := *h
+	l := len(old)
+	x := old[l-1]
+	*h = old[:l-1]
 	return x
 }
+
+func Sqrt2558(x int) int {
+	if x == 0 {
+		return 0
+	}
+
+	r := x
+	for r*r > x {
+		r = (r + x/r) / 2
+	}
+
+	return r
+}
+
+func Solution(gifts []int, k int) int64 {
+	ans := int64(0)
+	h := &heap2558{}
+	for _, n := range gifts {
+		heap.Push(h, n)
+	}
+	for ; k > 0; k-- {
+		top := heap.Pop(h).(int)
+		x := Sqrt2558(top)
+		heap.Push(h, x)
+	}
+	for h.Len() > 0 {
+		top := heap.Pop(h).(int)
+		ans += int64(top)
+	}
+	return ans
+}

leetcode/2501-2600/2558.Take-Gifts-From-the-Richest-Pile/Solution_test.go

@@ -10,30 +10,30 @@ func TestSolution(t *testing.T) {
 	//	测试用例
 	cases := []struct {
 		name   string
-		inputs bool
-		expect bool
+		gifts  []int
+		k      int
+		expect int64
 	}{
-		{"TestCase", true, true},
-		{"TestCase", true, true},
-		{"TestCase", false, false},
+		{"TestCase1", []int{25, 64, 9, 4, 100}, 4, 29},
+		{"TestCase2", []int{1, 1, 1, 1}, 4, 4},
 	}
 
 	//	开始测试
 	for i, c := range cases {
 		t.Run(c.name+" "+strconv.Itoa(i), func(t *testing.T) {
-			got := Solution(c.inputs)
+			got := Solution(c.gifts, c.k)
 			if !reflect.DeepEqual(got, c.expect) {
-				t.Fatalf("expected: %v, but got: %v, with inputs: %v",
-					c.expect, got, c.inputs)
+				t.Fatalf("expected: %v, but got: %v, with inputs: %v %v",
+					c.expect, got, c.gifts, c.k)
 			}
 		})
 	}
 }
 
-//	压力测试
+// 压力测试
 func BenchmarkSolution(b *testing.B) {
 }
 
-//	使用案列
+// 使用案列
 func ExampleSolution() {
 }