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BranchAndBound.java
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BranchAndBound.java
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import java.util.*;
import java.io.*;
/**
* Best First Branch and Bound Algorithm for the 0/1 Knapsack problem.
* This algorithm uses Lagrangian relaxation to prune the Branch and Bound tree.
* @author Shalin Shah
* Email: [email protected]
*/
public class BranchAndBound
{
public static void main(String [] args)
{
long start = System.currentTimeMillis();
LagrangianRelaxation.calculateLambda();
KNode incumbent = GreedySolution.runGreedyAlgorithm();
System.out.println("Greedy Solution - " + incumbent.value());
incumbent = RandomSearch.randomSearch(incumbent);
System.out.println("Improved Greedy Solution - " + incumbent.value());
incumbent = runBranchAndBound(incumbent);
long end = System.currentTimeMillis();
System.out.println((end-start) + " milliseconds.");
System.out.println("Optimum Value: " + incumbent.value());
System.out.println("Weight: " + incumbent.weight());
System.out.println(incumbent.getKnapsackContents());
}
public static KNode runBranchAndBound(KNode in)
{
KNode incumbent = new KNode((BitSet)in.getKnapsackContents().clone(), 0, in.weight(), in.value());
TreeSet heap = new TreeSet();
KNode node1 = new KNode(new BitSet(Constants.NUMBER_OBJECTS), 0, 0, 0);
KNode node2 = new KNode(new BitSet(Constants.NUMBER_OBJECTS), 0, 0, 0);
node1.addOne();
node2.addZero();
if(node1.maxValue() > incumbent.value())
heap.add(node1);
if(node2.maxValue() > incumbent.value())
heap.add(node2);
boolean heapEmpty = false;
while(!heap.isEmpty())
{
KNode node = (KNode)heap.first();
heap.remove(node);
while(node.getIndex() == Constants.NUMBER_OBJECTS)
{
node.fathom();
if(node.value() > incumbent.value() && Util.isValidSolution(node))
{
incumbent = node;
}
if(!heap.isEmpty())
{
node = (KNode)heap.first();
heap.remove(node);
}
else
{
heapEmpty = true;
break;
}
}
if(heapEmpty)
{
break;
}
/* Expand the node */
KNode node3 = new KNode((BitSet)node.getKnapsackContents().clone(), node.getIndex(), node.weight(), node.value());
KNode node4 = new KNode((BitSet)node.getKnapsackContents().clone(), node.getIndex(), node.weight(), node.value());
node3.addOne();
node4.addZero();
if(node3.maxValue() > incumbent.value() && Util.isValidSolution(node3))
heap.add(node3);
if(node4.maxValue() > incumbent.value() && Util.isValidSolution(node4))
heap.add(node4);
}
return incumbent;
}
}