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Open shell calculation of Li. Strange RDM1 occupation with half of electron and n_alpha - n_beta=0 #56
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Since you do not have |
For computational efficiency the code uses the singlet embedding strategy
to treat nonsinglet states with SU2 as described in Sharma and Chan.
Additional fictitious spins are added so that the final state is a singlet.
This means that the ensemble average over all Ms sectors is represented
rather than a given Ms sector.
I think it is possible to turn this off as an input option but I think the
two particle DM might not have been coded correctly without it. Sandeep is
this true? Huanchen can you check the input options?
On Thu, Feb 18, 2021 at 5:28 AM hczhai ***@***.***> wrote:
Since you do not have nonspinadapted in the input file, this is SU(2)
spin-adapted calculation (alpha = beta).
In the input file spin 1 means total spin 2S = 1.
If you want alpha and beta to be different, please add nonspinadapted in
the input file.
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@hczhai
@gkc1000 Thank you. |
You mean the final rdm is rdm taken from a mixed state?
|
(a) The singlet embedding is controlled by the internal variable |
In
It can also be nb-na=1. The code does not know which case it is. In the onepdm you get a mixture of the two cases. |
Using the FCIDUMP generated by the method proposed from previous issue I'm trying to calculate Li atom with 3 electrons.
Input file is
output reports that Spin=1
Finished Sweep with 1000 states and sweep energy for State [ 0 ] with Spin [ 1 ] :: -7.395656723881
but density matrix
onepdm.0.0.txt
has following occupationsSo, the non-paired electron is divided between spin-up and spin-down orbital and non-diagonal components are zero. The number of electrons for spin-up is 1.5, and n_alpha - n_beta = 0.
Why does it happen? I'm not sure it works correctly.
Best regards
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