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Mv.dual() method return wrong result #514
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The current implementation of Mv.dual() only multiply the input multivector by the pseudoscalar I in different ways according to the dual mode, but according to this: https://youtu.be/2AKt6adG_OI?t=1611&si=Z8VbJiqwMEVUlCW1, the implementation will not give correct result in some situations, the dual multivector *v of v should always produce this result: v (*v) = I, where I is the pseudoscalar. |
Hi @utensil, I found galgebra have no "dual inverse" (hodge star inverse
I am not sure how exactly they work when the pseudoscalar can not be normalized because of degenerate basis set, but definition 1 is specifically defined for projective GA which is always degenerate. However, https://www.rigidgeometricalgebra.org/wiki/index.php?title=Geometric_norm state for any degenerate basis like the pseudo scalar in projective GA, although it can not be normalized because the basis square to 0, the dual of a degenerate basis is always non-degenerate (like the dual of a degenerate pseudo scalar I is always a scalar which is non-degenerate), so we can "normalize" a degenerate basis like I by doing dual-inverse(normalize(dual(I))). It is absolutely beyond my math understanding so I am just mentioning this as a record.
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With the latest branch , per http://www.faculty.luther.edu/~macdonal/GAlgebraPrimer.pdf , the behavior you desire can be restored by adding a This means the dual will be calculated by
GAlgebra embraces as many conventions as possible, via modes. |
@utensil thanks for the explanation 👍 |
@mammalwong Issues reported by you are mostly fixed in the latest branch, except the ones marked with The branch will be included in the |
Ah, sorry, I missed that one. Thanks! |
To reproduce the bug, run this in a Jupyter/Colab cell:
Which outputs:
(-e_xyz, -e_xyz, 'I+')
Expected correct result:
(e_xyz, e_xyz, 'I+')
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