You are given a non-negative floating point number rounded to two decimal places celsius
, that denotes the temperature in Celsius.
You should convert Celsius into Kelvin and Fahrenheit and return it as an array ans = [kelvin, fahrenheit]
.
Return the array ans
. Answers within 10-5
of the actual answer will be accepted.
Note that:
Kelvin = Celsius + 273.15
Fahrenheit = Celsius * 1.80 + 32.00
Example 1:
Input: celsius = 36.50 Output: [309.65000,97.70000] Explanation: Temperature at 36.50 Celsius converted in Kelvin is 309.65 and converted in Fahrenheit is 97.70.
Example 2:
Input: celsius = 122.11 Output: [395.26000,251.79800] Explanation: Temperature at 122.11 Celsius converted in Kelvin is 395.26 and converted in Fahrenheit is 251.798.
Constraints:
0 <= celsius <= 1000
class Solution:
def convertTemperature(self, celsius: float) -> List[float]:
return [celsius + 273.15, celsius * 1.8 + 32]
class Solution {
public double[] convertTemperature(double celsius) {
return new double[] {celsius + 273.15, celsius * 1.8 + 32};
}
}
class Solution {
public:
vector<double> convertTemperature(double celsius) {
return {celsius + 273.15, celsius * 1.8 + 32};
}
};
func convertTemperature(celsius float64) []float64 {
return []float64{celsius + 273.15, celsius*1.8 + 32}
}
function convertTemperature(celsius: number): number[] {
return [celsius + 273.15, celsius * 1.8 + 32];
}
impl Solution {
pub fn convert_temperature(celsius: f64) -> Vec<f64> {
vec![celsius + 273.15, celsius * 1.8 + 32.0]
}
}
/**
* Note: The returned array must be malloced, assume caller calls free().
*/
double *convertTemperature(double celsius, int *returnSize) {
double *ans = malloc(sizeof(double) * 2);
ans[0] = celsius + 273.15;
ans[1] = celsius * 1.8 + 32;
*returnSize = 2;
return ans;
}