Skip to content

Latest commit

 

History

History
128 lines (100 loc) · 4.89 KB

README_EN.md

File metadata and controls

128 lines (100 loc) · 4.89 KB
Raw

2343. Query Kth Smallest Trimmed Number

中文文档

Description

You are given a 0-indexed array of strings nums, where each string is of equal length and consists of only digits.

You are also given a 0-indexed 2D integer array queries where queries[i] = [ki, trimi]. For each queries[i], you need to:

  • Trim each number in nums to its rightmost trimi digits.
  • Determine the index of the kith smallest trimmed number in nums. If two trimmed numbers are equal, the number with the lower index is considered to be smaller.
  • Reset each number in nums to its original length.

Return an array answer of the same length as queries, where answer[i] is the answer to the ith query.

Note:

  • To trim to the rightmost x digits means to keep removing the leftmost digit, until only x digits remain.
  • Strings in nums may contain leading zeros.

 

Example 1:

Input: nums = ["102","473","251","814"], queries = [[1,1],[2,3],[4,2],[1,2]]
Output: [2,2,1,0]
Explanation:
1. After trimming to the last digit, nums = ["2","3","1","4"]. The smallest number is 1 at index 2.
2. Trimmed to the last 3 digits, nums is unchanged. The 2nd smallest number is 251 at index 2.
3. Trimmed to the last 2 digits, nums = ["02","73","51","14"]. The 4th smallest number is 73.
4. Trimmed to the last 2 digits, the smallest number is 2 at index 0.
   Note that the trimmed number "02" is evaluated as 2.

Example 2:

Input: nums = ["24","37","96","04"], queries = [[2,1],[2,2]]
Output: [3,0]
Explanation:
1. Trimmed to the last digit, nums = ["4","7","6","4"]. The 2nd smallest number is 4 at index 3.
   There are two occurrences of 4, but the one at index 0 is considered smaller than the one at index 3.
2. Trimmed to the last 2 digits, nums is unchanged. The 2nd smallest number is 24.

 

Constraints:

  • 1 <= nums.length <= 100
  • 1 <= nums[i].length <= 100
  • nums[i] consists of only digits.
  • All nums[i].length are equal.
  • 1 <= queries.length <= 100
  • queries[i].length == 2
  • 1 <= ki <= nums.length
  • 1 <= trimi <= nums[i].length

 

Follow up: Could you use the Radix Sort Algorithm to solve this problem? What will be the complexity of that solution?

Solutions

Python3

class Solution:
    def smallestTrimmedNumbers(
        self, nums: List[str], queries: List[List[int]]
    ) -> List[int]:
        ans = []
        for k, t in queries:
            x = nums[:]
            for i, v in enumerate(x):
                x[i] = v[-t:]
            p = list(zip(x, range(len(x))))
            p.sort(key=lambda v: (int(v[0]), v[1]))
            ans.append(p[k - 1][1])
        return ans

Java

class Solution {
    public int[] smallestTrimmedNumbers(String[] nums, int[][] queries) {
        int n = queries.length;
        int m = nums.length;
        int[] ans = new int[n];
        for (int i = 0; i < n; ++i) {
            int k = queries[i][0], t = queries[i][1];
            String[][] arr = new String[m][2];
            for (int j = 0; j < m; ++j) {
                arr[j][0] = nums[j].substring(nums[j].length() - t);
                arr[j][1] = String.valueOf(j);
            }
            Arrays.sort(arr, (a, b) -> {
                int x = a[0].compareTo(b[0]);
                return x == 0 ? Long.compare(Integer.valueOf(a[1]), Integer.valueOf(b[1])) : x;
            });
            ans[i] = Integer.valueOf(arr[k - 1][1]);
        }
        return ans;
    }
}

TypeScript



...