README_EN.md

2148. Count Elements With Strictly Smaller and Greater Elements

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Description

Given an integer array nums, return the number of elements that have both a strictly smaller and a strictly greater element appear in nums.

 

Example 1:

Input: nums = [11,7,2,15]
Output: 2
Explanation: The element 7 has the element 2 strictly smaller than it and the element 11 strictly greater than it.
Element 11 has element 7 strictly smaller than it and element 15 strictly greater than it.
In total there are 2 elements having both a strictly smaller and a strictly greater element appear in nums.

Example 2:

Input: nums = [-3,3,3,90]
Output: 2
Explanation: The element 3 has the element -3 strictly smaller than it and the element 90 strictly greater than it.
Since there are two elements with the value 3, in total there are 2 elements having both a strictly smaller and a strictly greater element appear in nums.

 

Constraints:

• 1 <= nums.length <= 100
• -105 <= nums[i] <= 105

Solutions

Python3

class Solution:
    def countElements(self, nums: List[int]) -> int:
        mi, mx = min(nums), max(nums)
        return sum(mi < num < mx for num in nums)

Java

class Solution {

    public int countElements(int[] nums) {
        int mi = 1000000, mx = -1000000;
        for (int num : nums) {
            mi = Math.min(mi, num);
            mx = Math.max(mx, num);
        }
        int ans = 0;
        for (int num : nums) {
            if (mi < num && num < mx) {
                ++ans;
            }
        }
        return ans;
    }
}

C++

class Solution {
public:
    int countElements(vector<int>& nums) {
        int mi = 1e6, mx = -1e6;
        for (int num : nums) {
            mi = min(mi, num);
            mx = max(mx, num);
        }
        int ans = 0;
        for (int num : nums)
            if (mi < num && num < mx)
                ++ans;
        return ans;
    }
};

Go

func countElements(nums []int) int {
	mi, mx := int(1e6), -int(1e6)
	for _, num := range nums {
		if num < mi {
			mi = num
		}
		if num > mx {
			mx = num
		}
	}
	ans := 0
	for _, num := range nums {
		if mi < num && num < mx {
			ans++
		}
	}
	return ans
}

TypeScript

function countElements(nums: number[]): number {
    const min = Math.min(...nums),
        max = Math.max(...nums);
    let ans = 0;
    for (let i = 0; i < nums.length; ++i) {
        let cur = nums[i];
        if (cur < max && cur > min) {
            ++ans;
        }
    }
    return ans;
}

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