You are given a stream of points on the X-Y plane. Design an algorithm that:
- Adds new points from the stream into a data structure. Duplicate points are allowed and should be treated as different points.
- Given a query point, counts the number of ways to choose three points from the data structure such that the three points and the query point form an axis-aligned square with positive area.
An axis-aligned square is a square whose edges are all the same length and are either parallel or perpendicular to the x-axis and y-axis.
Implement the DetectSquares
class:
DetectSquares()
Initializes the object with an empty data structure.void add(int[] point)
Adds a new pointpoint = [x, y]
to the data structure.int count(int[] point)
Counts the number of ways to form axis-aligned squares with pointpoint = [x, y]
as described above.
Example 1:
Input ["DetectSquares", "add", "add", "add", "count", "count", "add", "count"] [[], [[3, 10]], [[11, 2]], [[3, 2]], [[11, 10]], [[14, 8]], [[11, 2]], [[11, 10]]] Output [null, null, null, null, 1, 0, null, 2]Explanation DetectSquares detectSquares = new DetectSquares(); detectSquares.add([3, 10]); detectSquares.add([11, 2]); detectSquares.add([3, 2]); detectSquares.count([11, 10]); // return 1. You can choose: // - The first, second, and third points detectSquares.count([14, 8]); // return 0. The query point cannot form a square with any points in the data structure. detectSquares.add([11, 2]); // Adding duplicate points is allowed. detectSquares.count([11, 10]); // return 2. You can choose: // - The first, second, and third points // - The first, third, and fourth points
Constraints:
point.length == 2
0 <= x, y <= 1000
- At most
3000
calls in total will be made toadd
andcount
.
class DetectSquares:
def __init__(self):
self.mp = defaultdict(Counter)
def add(self, point: List[int]) -> None:
x, y = point
self.mp[x][y] += 1
def count(self, point: List[int]) -> int:
x, y = point
ans = 0
if x not in self.mp:
return ans
xcnt = self.mp[x]
for x1, counter in self.mp.items():
if x1 != x:
d = x1 - x
ans += xcnt[y + d] * counter[y] * counter[y + d]
ans += xcnt[y - d] * counter[y] * counter[y - d]
return ans
class DetectSquares {
private Map<Integer, Map<Integer, Integer>> mp = new HashMap<>();
public DetectSquares() {
}
public void add(int[] point) {
int x = point[0], y = point[1];
if (!mp.containsKey(x)) {
mp.put(x, new HashMap<>());
}
mp.get(x).put(y, mp.get(x).getOrDefault(y, 0) + 1);
}
public int count(int[] point) {
int x = point[0], y = point[1];
int ans = 0;
if (!mp.containsKey(x)) {
return ans;
}
Map<Integer, Integer> xcnt = mp.get(x);
for (Map.Entry<Integer, Map<Integer, Integer>> e : mp.entrySet()) {
int x1 = e.getKey();
Map<Integer, Integer> counter = e.getValue();
if (x1 != x) {
int d = x1 - x;
ans += xcnt.getOrDefault(y + d, 0) * counter.getOrDefault(y, 0)
* counter.getOrDefault(y + d, 0);
ans += xcnt.getOrDefault(y - d, 0) * counter.getOrDefault(y, 0)
* counter.getOrDefault(y - d, 0);
}
}
return ans;
}
}
/**
* Your DetectSquares object will be instantiated and called as such:
* DetectSquares obj = new DetectSquares();
* obj.add(point);
* int param_2 = obj.count(point);
*/
class DetectSquares {
public:
unordered_map<int, unordered_map<int, int>> mp;
DetectSquares() {
}
void add(vector<int> point) {
int x = point[0], y = point[1];
++mp[x][y];
}
int count(vector<int> point) {
int x = point[0], y = point[1];
int ans = 0;
if (!mp.count(x)) return ans;
auto xcnt = mp[x];
for (auto e : mp) {
int x1 = e.first;
auto counter = e.second;
if (x1 != x) {
int d = x1 - x;
ans += xcnt[y + d] * counter[y] * counter[y + d];
ans += xcnt[y - d] * counter[y] * counter[y - d];
}
}
return ans;
}
};
/**
* Your DetectSquares object will be instantiated and called as such:
* DetectSquares* obj = new DetectSquares();
* obj->add(point);
* int param_2 = obj->count(point);
*/