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1950. Maximum of Minimum Values in All Subarrays

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Description

You are given an integer array nums of size n. You are asked to solve n queries for each integer i in the range 0 <= i < n.

To solve the ith query:

1. Find the minimum value in each possible subarray of size i + 1 of the array nums.
2. Find the maximum of those minimum values. This maximum is the answer to the query.

Return a 0-indexed integer array ans of size n such that ans[i] is the answer to the ith query.

A subarray is a contiguous sequence of elements in an array.

 

Example 1:

Input: nums = [0,1,2,4]
Output: [4,2,1,0]
Explanation:
i=0:
- The subarrays of size 1 are [0], [1], [2], [4]. The minimum values are 0, 1, 2, 4.
- The maximum of the minimum values is 4.
i=1:
- The subarrays of size 2 are [0,1], [1,2], [2,4]. The minimum values are 0, 1, 2.
- The maximum of the minimum values is 2.
i=2:
- The subarrays of size 3 are [0,1,2], [1,2,4]. The minimum values are 0, 1.
- The maximum of the minimum values is 1.
i=3:
- There is one subarray of size 4, which is [0,1,2,4]. The minimum value is 0.
- There is only one value, so the maximum is 0.

Example 2:

Input: nums = [10,20,50,10]
Output: [50,20,10,10]
Explanation:
i=0:
- The subarrays of size 1 are [10], [20], [50], [10]. The minimum values are 10, 20, 50, 10.
- The maximum of the minimum values is 50.
i=1:
- The subarrays of size 2 are [10,20], [20,50], [50,10]. The minimum values are 10, 20, 10.
- The maximum of the minimum values is 20.
i=2:
- The subarrays of size 3 are [10,20,50], [20,50,10]. The minimum values are 10, 10.
- The maximum of the minimum values is 10.
i=3:
- There is one subarray of size 4, which is [10,20,50,10]. The minimum value is 10.
- There is only one value, so the maximum is 10.

 

Constraints:

• n == nums.length
• 1 <= n <= 105
• 0 <= nums[i] <= 109

Solutions

Python3

Java

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