There is a biker going on a road trip. The road trip consists of n + 1
points at different altitudes. The biker starts his trip on point 0
with altitude equal 0
.
You are given an integer array gain
of length n
where gain[i]
is the net gain in altitude between points i
and i + 1
for all (0 <= i < n)
. Return the highest altitude of a point.
Example 1:
Input: gain = [-5,1,5,0,-7] Output: 1 Explanation: The altitudes are [0,-5,-4,1,1,-6]. The highest is 1.
Example 2:
Input: gain = [-4,-3,-2,-1,4,3,2] Output: 0 Explanation: The altitudes are [0,-4,-7,-9,-10,-6,-3,-1]. The highest is 0.
Constraints:
n == gain.length
1 <= n <= 100
-100 <= gain[i] <= 100
class Solution:
def largestAltitude(self, gain: List[int]) -> int:
return max(accumulate(gain, initial=0))
class Solution:
def largestAltitude(self, gain: List[int]) -> int:
ans = s = 0
for v in gain:
s += v
ans = max(ans, s)
return ans
class Solution {
public int largestAltitude(int[] gain) {
int ans = 0, s = 0;
for (int v : gain) {
s += v;
ans = Math.max(ans, s);
}
return ans;
}
}
class Solution {
public:
int largestAltitude(vector<int>& gain) {
int ans = 0, s = 0;
for (int v : gain) s += v, ans = max(ans, s);
return ans;
}
};
func largestAltitude(gain []int) (ans int) {
s := 0
for _, v := range gain {
s += v
if ans < s {
ans = s
}
}
return
}
/**
* @param {number[]} gain
* @return {number}
*/
var largestAltitude = function (gain) {
let ans = 0;
let s = 0;
for (const v of gain) {
s += v;
ans = Math.max(ans, s);
}
return ans;
};