You are given a string allowed
consisting of distinct characters and an array of strings words
. A string is consistent if all characters in the string appear in the string allowed
.
Return the number of consistent strings in the array words
.
Example 1:
Input: allowed = "ab", words = ["ad","bd","aaab","baa","badab"] Output: 2 Explanation: Strings "aaab" and "baa" are consistent since they only contain characters 'a' and 'b'.
Example 2:
Input: allowed = "abc", words = ["a","b","c","ab","ac","bc","abc"] Output: 7 Explanation: All strings are consistent.
Example 3:
Input: allowed = "cad", words = ["cc","acd","b","ba","bac","bad","ac","d"] Output: 4 Explanation: Strings "cc", "acd", "ac", and "d" are consistent.
Constraints:
1 <= words.length <= 104
1 <= allowed.length <= 26
1 <= words[i].length <= 10
- The characters in
allowed
are distinct. words[i]
andallowed
contain only lowercase English letters.
class Solution:
def countConsistentStrings(self, allowed: str, words: List[str]) -> int:
s = set(allowed)
return sum(all(c in s for c in w) for w in words)
class Solution:
def countConsistentStrings(self, allowed: str, words: List[str]) -> int:
def f(w):
return reduce(or_, (1 << (ord(c) - ord('a')) for c in w))
mask = f(allowed)
return sum((mask | f(w)) == mask for w in words)
class Solution {
public int countConsistentStrings(String allowed, String[] words) {
boolean[] s = new boolean[26];
for (char c : allowed.toCharArray()) {
s[c - 'a'] = true;
}
int ans = 0;
for (String w : words) {
if (check(w, s)) {
++ans;
}
}
return ans;
}
private boolean check(String w, boolean[] s) {
for (int i = 0; i < w.length(); ++i) {
if (!s[w.charAt(i) - 'a']) {
return false;
}
}
return true;
}
}
class Solution {
public int countConsistentStrings(String allowed, String[] words) {
int mask = f(allowed);
int ans = 0;
for (String w : words) {
if ((mask | f(w)) == mask) {
++ans;
}
}
return ans;
}
private int f(String w) {
int mask = 0;
for (int i = 0; i < w.length(); ++i) {
mask |= 1 << (w.charAt(i) - 'a');
}
return mask;
}
}
class Solution {
public:
int countConsistentStrings(string allowed, vector<string>& words) {
bitset<26> s;
for (auto& c : allowed) s[c - 'a'] = 1;
int ans = 0;
auto check = [&](string& w) {
for (auto& c : w) if (!s[c - 'a']) return false;
return true;
};
for (auto& w : words) ans += check(w);
return ans;
}
};
class Solution {
public:
int countConsistentStrings(string allowed, vector<string>& words) {
auto f = [](string& w) {
int mask = 0;
for (auto& c : w) mask |= 1 << (c - 'a');
return mask;
};
int mask = f(allowed);
int ans = 0;
for (auto& w : words) ans += (mask | f(w)) == mask;
return ans;
}
};
func countConsistentStrings(allowed string, words []string) (ans int) {
s := [26]bool{}
for _, c := range allowed {
s[c-'a'] = true
}
check := func(w string) bool {
for _, c := range w {
if !s[c-'a'] {
return false
}
}
return true
}
for _, w := range words {
if check(w) {
ans++
}
}
return ans
}
func countConsistentStrings(allowed string, words []string) (ans int) {
f := func(w string) (mask int) {
for _, c := range w {
mask |= 1 << (c - 'a')
}
return
}
mask := f(allowed)
for _, w := range words {
if (mask | f(w)) == mask {
ans++
}
}
return
}
int countConsistentStrings(char *allowed, char **words, int wordsSize) {
int n = strlen(allowed);
int make[26] = {0};
for (int i = 0; i < n; i++) {
make[allowed[i] - 'a'] = 1;
}
int ans = wordsSize;
for (int i = 0; i < wordsSize; i++) {
char *word = words[i];
for (int j = 0; j < strlen(word); j++) {
if (!make[word[j] - 'a']) {
ans--;
break;
}
}
}
return ans;
}
int helper(char *s) {
int res = 0;
int n = strlen(s);
for (int i = 0; i < n; i++) {
res |= 1 << (s[i] - 'a');
}
return res;
}
int countConsistentStrings(char *allowed, char **words, int wordsSize) {
int mask = helper(allowed);
int ans = 0;
for (int i = 0; i < wordsSize; i++) {
if ((mask | helper(words[i])) == mask) {
ans++;
}
}
return ans;
}
function countConsistentStrings(allowed: string, words: string[]): number {
const set = new Set([...allowed]);
const n = words.length;
let ans = n;
for (const word of words) {
for (const c of word) {
if (!set.has(c)) {
ans--;
break;
}
}
}
return ans;
}
function countConsistentStrings(allowed: string, words: string[]): number {
const helper = (s: string) => {
let res = 0;
for (const c of s) {
res |= 1 << (c.charCodeAt(0) - 'a'.charCodeAt(0));
}
return res;
};
const mask = helper(allowed);
let ans = 0;
for (const word of words) {
if ((mask | helper(word)) === mask) {
ans++;
}
}
return ans;
}
impl Solution {
pub fn count_consistent_strings(allowed: String, words: Vec<String>) -> i32 {
let n = words.len();
let mut make = [false; 26];
for c in allowed.as_bytes() {
make[(c - b'a') as usize] = true;
}
let mut ans = n as i32;
for word in words.iter() {
for c in word.as_bytes().iter() {
if !make[(c - b'a') as usize] {
ans -= 1;
break;
}
}
}
ans
}
}
impl Solution {
fn helper(s: &String) -> i32 {
let mut res = 0;
for c in s.as_bytes().iter() {
res |= 1 << (c - b'a') as i32;
}
res
}
pub fn count_consistent_strings(allowed: String, words: Vec<String>) -> i32 {
let mask = Self::helper(&allowed);
let mut ans = 0;
for word in words.iter() {
if (mask | Self::helper(word)) == mask {
ans += 1;
}
}
ans
}
}