README_EN.md

1508. Range Sum of Sorted Subarray Sums

中文文档

Description

You are given the array nums consisting of n positive integers. You computed the sum of all non-empty continuous subarrays from the array and then sorted them in non-decreasing order, creating a new array of n * (n + 1) / 2 numbers.

Return the sum of the numbers from index left to index right (indexed from 1), inclusive, in the new array. Since the answer can be a huge number return it modulo 109 + 7.

 

Example 1:

Input: nums = [1,2,3,4], n = 4, left = 1, right = 5
Output: 13 
Explanation: All subarray sums are 1, 3, 6, 10, 2, 5, 9, 3, 7, 4. After sorting them in non-decreasing order we have the new array [1, 2, 3, 3, 4, 5, 6, 7, 9, 10]. The sum of the numbers from index le = 1 to ri = 5 is 1 + 2 + 3 + 3 + 4 = 13. 

Example 2:

Input: nums = [1,2,3,4], n = 4, left = 3, right = 4
Output: 6
Explanation: The given array is the same as example 1. We have the new array [1, 2, 3, 3, 4, 5, 6, 7, 9, 10]. The sum of the numbers from index le = 3 to ri = 4 is 3 + 3 = 6.

Example 3:

Input: nums = [1,2,3,4], n = 4, left = 1, right = 10
Output: 50

 

Constraints:

• n == nums.length
• 1 <= nums.length <= 1000
• 1 <= nums[i] <= 100
• 1 <= left <= right <= n * (n + 1) / 2

Solutions

Python3

class Solution:
    def rangeSum(self, nums: List[int], n: int, left: int, right: int) -> int:
        arr = []
        for i in range(n):
            s = 0
            for j in range(i, n):
                s += nums[j]
                arr.append(s)
        arr.sort()
        MOD = 10**9 + 7
        return sum(arr[left - 1 : right]) % MOD

Java

class Solution {
    private static final int MOD = (int) 1e9 + 7;

    public int rangeSum(int[] nums, int n, int left, int right) {
        int[] arr = new int[n * (n + 1) / 2];
        int idx = 0;
        for (int i = 0; i < n; ++i) {
            int s = 0;
            for (int j = i; j < n; ++j) {
                s += nums[j];
                arr[idx++] = s;
            }
        }
        Arrays.sort(arr);
        int ans = 0;
        for (int i = left - 1; i < right; ++i) {
            ans = (ans + arr[i]) % MOD;
        }
        return ans;
    }
}

Go

func rangeSum(nums []int, n int, left int, right int) int {
	var arr []int
	for i := 0; i < n; i++ {
		s := 0
		for j := i; j < n; j++ {
			s += nums[j]
			arr = append(arr, s)
		}
	}
	sort.Ints(arr)
	mod := int(1e9) + 7
	ans := 0
	for i := left - 1; i < right; i++ {
		ans = (ans + arr[i]) % mod
	}
	return ans
}

...