Table Activities:
+-------------+---------+ | Column Name | Type | +-------------+---------+ | sell_date | date | | product | varchar | +-------------+---------+ There is no primary key for this table, it may contain duplicates. Each row of this table contains the product name and the date it was sold in a market.
Write an SQL query to find for each date the number of different products sold and their names.
The sold products names for each date should be sorted lexicographically.
Return the result table ordered by sell_date.
The query result format is in the following example.
Example 1:
Input: Activities table: +------------+------------+ | sell_date | product | +------------+------------+ | 2020-05-30 | Headphone | | 2020-06-01 | Pencil | | 2020-06-02 | Mask | | 2020-05-30 | Basketball | | 2020-06-01 | Bible | | 2020-06-02 | Mask | | 2020-05-30 | T-Shirt | +------------+------------+ Output: +------------+----------+------------------------------+ | sell_date | num_sold | products | +------------+----------+------------------------------+ | 2020-05-30 | 3 | Basketball,Headphone,T-shirt | | 2020-06-01 | 2 | Bible,Pencil | | 2020-06-02 | 1 | Mask | +------------+----------+------------------------------+ Explanation: For 2020-05-30, Sold items were (Headphone, Basketball, T-shirt), we sort them lexicographically and separate them by a comma. For 2020-06-01, Sold items were (Pencil, Bible), we sort them lexicographically and separate them by a comma. For 2020-06-02, the Sold item is (Mask), we just return it.
SELECT
sell_date,
COUNT(DISTINCT product) AS num_sold,
GROUP_CONCAT(DISTINCT product
ORDER BY product ASC
SEPARATOR ',') AS products
FROM
Activities
GROUP BY sell_date
ORDER BY sell_date ASC;