There are a total of numCourses
courses you have to take, labeled from 0
to numCourses - 1
. You are given an array prerequisites
where prerequisites[i] = [ai, bi]
indicates that you must take course ai
first if you want to take course bi
.
- For example, the pair
[0, 1]
indicates that you have to take course0
before you can take course1
.
Prerequisites can also be indirect. If course a
is a prerequisite of course b
, and course b
is a prerequisite of course c
, then course a
is a prerequisite of course c
.
You are also given an array queries
where queries[j] = [uj, vj]
. For the jth
query, you should answer whether course uj
is a prerequisite of course vj
or not.
Return a boolean array answer
, where answer[j]
is the answer to the jth
query.
Example 1:
Input: numCourses = 2, prerequisites = [[1,0]], queries = [[0,1],[1,0]] Output: [false,true] Explanation: The pair [1, 0] indicates that you have to take course 1 before you can take course 0. Course 0 is not a prerequisite of course 1, but the opposite is true.
Example 2:
Input: numCourses = 2, prerequisites = [], queries = [[1,0],[0,1]] Output: [false,false] Explanation: There are no prerequisites, and each course is independent.
Example 3:
Input: numCourses = 3, prerequisites = [[1,2],[1,0],[2,0]], queries = [[1,0],[1,2]] Output: [true,true]
Constraints:
2 <= numCourses <= 100
0 <= prerequisites.length <= (numCourses * (numCourses - 1) / 2)
prerequisites[i].length == 2
0 <= ai, bi <= n - 1
ai != bi
- All the pairs
[ai, bi]
are unique. - The prerequisites graph has no cycles.
1 <= queries.length <= 104
0 <= ui, vi <= n - 1
ui != vi
DFS.
class Solution:
def checkIfPrerequisite(
self, numCourses: int, prerequisites: List[List[int]], queries: List[List[int]]
) -> List[bool]:
@cache
def dfs(a, b):
if b in g[a] or a == b:
return True
for c in g[a]:
if dfs(c, b):
return True
return False
g = defaultdict(set)
for a, b in prerequisites:
g[a].add(b)
return [dfs(a, b) for a, b in queries]
class Solution {
public List<Boolean> checkIfPrerequisite(
int numCourses, int[][] prerequisites, int[][] queries) {
int[][] g = new int[numCourses][numCourses];
for (int i = 0; i < numCourses; ++i) {
Arrays.fill(g[i], -1);
}
for (int[] e : prerequisites) {
int a = e[0], b = e[1];
g[a][b] = 1;
}
List<Boolean> ans = new ArrayList<>();
for (int[] e : queries) {
int a = e[0], b = e[1];
ans.add(dfs(a, b, g));
}
return ans;
}
private boolean dfs(int a, int b, int[][] g) {
if (g[a][b] != -1) {
return g[a][b] == 1;
}
if (a == b) {
g[a][b] = 1;
return true;
}
for (int i = 0; i < g[a].length; ++i) {
if (g[a][i] == 1 && dfs(i, b, g)) {
g[a][b] = 1;
return true;
}
}
g[a][b] = 0;
return false;
}
}
class Solution {
public:
vector<bool> checkIfPrerequisite(int numCourses, vector<vector<int>>& prerequisites, vector<vector<int>>& queries) {
vector<vector<int>> g(numCourses, vector<int>(numCourses, -1));
for (auto& e : prerequisites) {
int a = e[0], b = e[1];
g[a][b] = 1;
}
vector<bool> ans;
for (auto& e : queries) {
int a = e[0], b = e[1];
ans.push_back(dfs(a, b, g));
}
return ans;
}
bool dfs(int a, int b, vector<vector<int>>& g) {
if (g[a][b] != -1) return g[a][b] == 1;
if (a == b) {
g[a][b] = 1;
return true;
}
for (int i = 0; i < g[a].size(); ++i) {
if (g[a][i] == 1 && dfs(i, b, g)) {
g[a][b] = 1;
return true;
}
}
g[a][b] = 0;
return false;
}
};
func checkIfPrerequisite(numCourses int, prerequisites [][]int, queries [][]int) []bool {
g := make([][]int, numCourses)
for i := range g {
g[i] = make([]int, numCourses)
for j := range g[i] {
g[i][j] = -1
}
}
for _, e := range prerequisites {
a, b := e[0], e[1]
g[a][b] = 1
}
var ans []bool
var dfs func(a, b int) bool
dfs = func(a, b int) bool {
if g[a][b] != -1 {
return g[a][b] == 1
}
if a == b {
g[a][b] = 1
return true
}
for i, c := range g[a] {
if c == 1 && dfs(i, b) {
g[a][b] = 1
return true
}
}
g[a][b] = 0
return false
}
for _, e := range queries {
a, b := e[0], e[1]
ans = append(ans, dfs(a, b))
}
return ans
}