You are given an integer num
. You will apply the following steps exactly two times:
- Pick a digit
x (0 <= x <= 9)
. - Pick another digit
y (0 <= y <= 9)
. The digity
can be equal tox
. - Replace all the occurrences of
x
in the decimal representation ofnum
byy
. - The new integer cannot have any leading zeros, also the new integer cannot be 0.
Let a
and b
be the results of applying the operations to num
the first and second times, respectively.
Return the max difference between a
and b
.
Example 1:
Input: num = 555 Output: 888 Explanation: The first time pick x = 5 and y = 9 and store the new integer in a. The second time pick x = 5 and y = 1 and store the new integer in b. We have now a = 999 and b = 111 and max difference = 888
Example 2:
Input: num = 9 Output: 8 Explanation: The first time pick x = 9 and y = 9 and store the new integer in a. The second time pick x = 9 and y = 1 and store the new integer in b. We have now a = 9 and b = 1 and max difference = 8
Constraints:
1 <= num <= 10
8
class Solution:
def maxDiff(self, num: int) -> int:
a, b = str(num), str(num)
for c in a:
if c != '9':
a = a.replace(c, '9')
break
for i, c in enumerate(b):
if i == 0:
if c != '1':
b = b.replace(c, '1')
break
else:
if c != '0' and c != b[0]:
b = b.replace(c, '0')
break
return int(a) - int(b)
class Solution {
public int maxDiff(int num) {
String a = String.valueOf(num);
String b = String.valueOf(num);
for (char c : a.toCharArray()) {
if (c != '9') {
a = a.replaceAll(String.valueOf(c), "9");
break;
}
}
for (int i = 0; i < b.length(); ++i) {
char c = b.charAt(i);
if (i == 0) {
if (c != '1') {
b = b.replaceAll(String.valueOf(c), "1");
break;
}
} else {
if (c != '0' && c != b.charAt(0)) {
b = b.replaceAll(String.valueOf(c), "0");
break;
}
}
}
return Integer.parseInt(a) - Integer.parseInt(b);
}
}
func maxDiff(num int) int {
a, b := num, num
s := strconv.Itoa(num)
for i := range s {
if s[i] != '9' {
a, _ = strconv.Atoi(strings.ReplaceAll(s, string(s[i]), "9"))
break
}
}
if s[0] > '1' {
b, _ = strconv.Atoi(strings.ReplaceAll(s, string(s[0]), "1"))
} else {
for i := 1; i < len(s); i++ {
if s[i] != '0' && s[i] != s[0] {
b, _ = strconv.Atoi(strings.ReplaceAll(s, string(s[i]), "0"))
break
}
}
}
return a - b
}