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1379. Find a Corresponding Node of a Binary Tree in a Clone of That Tree

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Description

Given two binary trees original and cloned and given a reference to a node target in the original tree.

The cloned tree is a copy of the original tree.

Return a reference to the same node in the cloned tree.

Note that you are not allowed to change any of the two trees or the target node and the answer must be a reference to a node in the cloned tree.

 

Example 1:

Input: tree = [7,4,3,null,null,6,19], target = 3
Output: 3
Explanation: In all examples the original and cloned trees are shown. The target node is a green node from the original tree. The answer is the yellow node from the cloned tree.

Example 2:

Input: tree = [7], target =  7
Output: 7

Example 3:

Input: tree = [8,null,6,null,5,null,4,null,3,null,2,null,1], target = 4
Output: 4

 

Constraints:

• The number of nodes in the tree is in the range [1, 104].
• The values of the nodes of the tree are unique.
• target node is a node from the original tree and is not null.

 

Follow up: Could you solve the problem if repeated values on the tree are allowed?

Solutions

Python3

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None


class Solution:
    def getTargetCopy(
        self, original: TreeNode, cloned: TreeNode, target: TreeNode
    ) -> TreeNode:
        res = None

        def dfs(original, cloned):
            nonlocal res
            if cloned is None:
                return
            if original == target:
                res = cloned
                return
            dfs(original.left, cloned.left)
            dfs(original.right, cloned.right)

        dfs(original, cloned)
        return res

Java

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */

class Solution {
    private TreeNode res;

    public final TreeNode getTargetCopy(
        final TreeNode original, final TreeNode cloned, final TreeNode target) {
        dfs(original, cloned, target);
        return res;
    }

    private void dfs(TreeNode original, TreeNode cloned, TreeNode target) {
        if (cloned == null) {
            return;
        }
        if (original == target) {
            res = cloned;
            return;
        }
        dfs(original.left, cloned.left, target);
        dfs(original.right, cloned.right, target);
    }
}

C++

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */

class Solution {
public:
    TreeNode* res;

    TreeNode* getTargetCopy(TreeNode* original, TreeNode* cloned, TreeNode* target) {
        dfs(original, cloned, target);
        return res;
    }

    void dfs(TreeNode* original, TreeNode* cloned, TreeNode* target) {
        if (!cloned) return;
        if (original == target) {
            res = cloned;
            return;
        }
        dfs(original->left, cloned->left, target);
        dfs(original->right, cloned->right, target);
    }
};

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