README_EN.md

1108. Defanging an IP Address

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Description

Given a valid (IPv4) IP address, return a defanged version of that IP address.

A defanged IP address replaces every period "." with "[.]".

 

Example 1:

Input: address = "1.1.1.1"

Output: "1[.]1[.]1[.]1"

Example 2:

Input: address = "255.100.50.0"

Output: "255[.]100[.]50[.]0"

 

Constraints:

<li>The given <code>address</code> is a valid IPv4 address.</li>

Solutions

Python3

class Solution:
    def defangIPaddr(self, address: str) -> str:
        return address.replace('.', '[.]')

Java

class Solution {
    public String defangIPaddr(String address) {
        return address.replace(".", "[.]");
    }
}

TypeScript

function defangIPaddr(address: string): string {
    return address.split('.').join('[.]');
}

C++

class Solution {
public:
    string defangIPaddr(string address) {
        for (int i = address.size(); i >= 0; --i) {
            if (address[i] == '.') {
                address.replace(i, 1, "[.]");
            }
        }
        return address;
    }
};

Go

func defangIPaddr(address string) string {
	return strings.Replace(address, ".", "[.]", -1)
}

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