README_EN.md

643. Maximum Average Subarray I

中文文档

Description

You are given an integer array nums consisting of n elements, and an integer k.

Find a contiguous subarray whose length is equal to k that has the maximum average value and return this value. Any answer with a calculation error less than 10-5 will be accepted.

 

Example 1:

Input: nums = [1,12,-5,-6,50,3], k = 4
Output: 12.75000
Explanation: Maximum average is (12 - 5 - 6 + 50) / 4 = 51 / 4 = 12.75

Example 2:

Input: nums = [5], k = 1
Output: 5.00000

 

Constraints:

• n == nums.length
• 1 <= k <= n <= 105
• -104 <= nums[i] <= 104

Solutions

Slide window.

Python3

class Solution:
    def findMaxAverage(self, nums: List[int], k: int) -> float:
        s = sum(nums[:k])
        ans = s
        for i in range(k, len(nums)):
            s += nums[i] - nums[i - k]
            ans = max(ans, s)
        return ans / k

Java

class Solution {
    public double findMaxAverage(int[] nums, int k) {
        int s = 0;
        for (int i = 0; i < k; ++i) {
            s += nums[i];
        }
        int ans = s;
        for (int i = k; i < nums.length; ++i) {
            s += (nums[i] - nums[i - k]);
            ans = Math.max(ans, s);
        }
        return ans * 1.0 / k;
    }
}

TypeScript

function findMaxAverage(nums: number[], k: number): number {
    let n = nums.length;
    let ans = 0;
    let sum = 0;
    // 前k
    for (let i = 0; i < k; i++) {
        sum += nums[i];
    }
    ans = sum;
    for (let i = k; i < n; i++) {
        sum += nums[i] - nums[i - k];
        ans = Math.max(ans, sum);
    }
    return ans / k;
}

Rust

impl Solution {
    pub fn find_max_average(nums: Vec<i32>, k: i32) -> f64 {
        let k = k as usize;
        let n = nums.len();
        let mut sum = nums.iter().take(k).sum::<i32>();
        let mut max = sum;
        for i in k..n {
            sum += nums[i] - nums[i - k];
            max = max.max(sum);
        }
        f64::from(max) / f64::from(k as i32)
    }
}

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