Table: Employee
+-------------+------+ | Column Name | Type | +-------------+------+ | id | int | | salary | int | +-------------+------+ id is the primary key column for this table. Each row of this table contains information about the salary of an employee.
Write an SQL query to report the second highest salary from the Employee
table. If there is no second highest salary, the query should report null
.
The query result format is in the following example.
Example 1:
Input: Employee table: +----+--------+ | id | salary | +----+--------+ | 1 | 100 | | 2 | 200 | | 3 | 300 | +----+--------+ Output: +---------------------+ | SecondHighestSalary | +---------------------+ | 200 | +---------------------+
Example 2:
Input: Employee table: +----+--------+ | id | salary | +----+--------+ | 1 | 100 | +----+--------+ Output: +---------------------+ | SecondHighestSalary | +---------------------+ | null | +---------------------+
Solution 1: Use Sub Query and LIMIT.
# Write your MySQL query statement below
SELECT
(
SELECT DISTINCT Salary
FROM Employee
ORDER BY Salary DESC
LIMIT 1 OFFSET 1
) AS SecondHighestSalary;
Solution 2: Use MAX()
function.
# Write your MySQL query statement below
SELECT MAX(Salary) AS SecondHighestSalary
FROM Employee
WHERE Salary < (
SELECT MAX(Salary)
FROM Employee
);