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剑指 Offer II 066. 单词之和

题目描述

实现一个 MapSum 类，支持两个方法，insert 和 sum：

• MapSum() 初始化 MapSum 对象
• void insert(String key, int val) 插入 key-val 键值对，字符串表示键 key ，整数表示值 val 。如果键 key 已经存在，那么原来的键值对将被替代成新的键值对。
• int sum(string prefix) 返回所有以该前缀 prefix 开头的键 key 的值的总和。

 

示例：

输入：
inputs = ["MapSum", "insert", "sum", "insert", "sum"]
inputs = [[], ["apple", 3], ["ap"], ["app", 2], ["ap"]]
输出：
[null, null, 3, null, 5]

解释：
MapSum mapSum = new MapSum();
mapSum.insert("apple", 3);  
mapSum.sum("ap");           // return 3 (apple = 3)
mapSum.insert("app", 2);    
mapSum.sum("ap");           // return 5 (apple + app = 3 + 2 = 5)

 

提示：

• 1 <= key.length, prefix.length <= 50
• key 和 prefix 仅由小写英文字母组成
• 1 <= val <= 1000
• 最多调用 50 次 insert 和 sum

 

注意：本题与主站 677 题相同： https://leetcode.cn/problems/map-sum-pairs/

解法

利用哈希表存储每个键的所有前缀子串。

Python3

class MapSum:
    def __init__(self):
        """
        Initialize your data structure here.
        """
        self.data = defaultdict(int)
        self.t = defaultdict(int)

    def insert(self, key: str, val: int) -> None:
        old = self.t[key]
        self.t[key] = val
        for i in range(1, len(key) + 1):
            self.data[key[:i]] += val - old

    def sum(self, prefix: str) -> int:
        return self.data[prefix]


# Your MapSum object will be instantiated and called as such:
# obj = MapSum()
# obj.insert(key,val)
# param_2 = obj.sum(prefix)

Java

class MapSum {
    private Map<String, Integer> data;
    private Map<String, Integer> t;

    /** Initialize your data structure here. */
    public MapSum() {
        data = new HashMap<>();
        t = new HashMap<>();
    }

    public void insert(String key, int val) {
        int old = t.getOrDefault(key, 0);
        t.put(key, val);
        for (int i = 1; i < key.length() + 1; ++i) {
            String k = key.substring(0, i);
            data.put(k, data.getOrDefault(k, 0) + (val - old));
        }
    }

    public int sum(String prefix) {
        return data.getOrDefault(prefix, 0);
    }
}

/**
 * Your MapSum object will be instantiated and called as such:
 * MapSum obj = new MapSum();
 * obj.insert(key,val);
 * int param_2 = obj.sum(prefix);
 */

C++

class MapSum {
public:
    unordered_map<string, int> data;
    unordered_map<string, int> t;

    /** Initialize your data structure here. */
    MapSum() {
    }

    void insert(string key, int val) {
        int old = t[key];
        t[key] = val;
        for (int i = 1; i < key.size() + 1; ++i) {
            string k = key.substr(0, i);
            data[k] += (val - old);
        }
    }

    int sum(string prefix) {
        return data[prefix];
    }
};

/**
 * Your MapSum object will be instantiated and called as such:
 * MapSum* obj = new MapSum();
 * obj->insert(key,val);
 * int param_2 = obj->sum(prefix);
 */

Go

type MapSum struct {
	data map[string]int
	t    map[string]int
}

/** Initialize your data structure here. */
func Constructor() MapSum {
	return MapSum{
		data: make(map[string]int),
		t:    make(map[string]int),
	}
}

func (this *MapSum) Insert(key string, val int) {
	old := this.t[key]
	this.t[key] = val
	for i := 1; i < len(key)+1; i++ {
		k := key[:i]
		this.data[k] += (val - old)
	}
}

func (this *MapSum) Sum(prefix string) int {
	return this.data[prefix]
}

/**
 * Your MapSum object will be instantiated and called as such:
 * obj := Constructor();
 * obj.Insert(key,val);
 * param_2 := obj.Sum(prefix);
 */

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