编写一个函数,不用临时变量,直接交换numbers = [a, b]
中a
与b
的值。
示例:
输入: numbers = [1,2] 输出: [2,1]
提示:
numbers.length == 2
异或运算。
class Solution:
def swapNumbers(self, numbers: List[int]) -> List[int]:
numbers[0] ^= numbers[1]
numbers[1] ^= numbers[0]
numbers[0] ^= numbers[1]
return numbers
class Solution {
public int[] swapNumbers(int[] numbers) {
numbers[0] ^= numbers[1];
numbers[1] ^= numbers[0];
numbers[0] ^= numbers[1];
return numbers;
}
}
function swapNumbers(numbers: number[]): number[] {
numbers[0] ^= numbers[1];
numbers[1] ^= numbers[0];
numbers[0] ^= numbers[1];
return numbers;
}
function swapNumbers(numbers: number[]): number[] {
[numbers[0], numbers[1]] = [numbers[1], numbers[0]];
return numbers;
}
class Solution {
public:
vector<int> swapNumbers(vector<int>& numbers) {
numbers[0] ^= numbers[1];
numbers[1] ^= numbers[0];
numbers[0] ^= numbers[1];
return numbers;
}
};
func swapNumbers(numbers []int) []int {
numbers[0] ^= numbers[1]
numbers[1] ^= numbers[0]
numbers[0] ^= numbers[1]
return numbers
}