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Implement PERSIST #148

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bendk opened this issue Aug 8, 2018 · 0 comments
Open

Implement PERSIST #148

bendk opened this issue Aug 8, 2018 · 0 comments

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@bendk
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bendk commented Aug 8, 2018

I think something like this could work:

    def persist(self, key):
        key = self._encode(key)
        if key in self.redis and key in self.timeouts:
            del self.timeouts[key]
            return 1
        else:
            return 0
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@bendk