Given an integer array nums
, find a contiguous non-empty subarray within the array that has the largest product, and return the product.
It is guaranteed that the answer will fit in a 32-bit integer.
A subarray is a contiguous subsequence of the array.
Example 1:
Input: nums = [2,3,-2,4] Output: 6 Explanation: [2,3] has the largest product 6.
Example 2:
Input: nums = [-2,0,-1] Output: 0 Explanation: The result cannot be 2, because [-2,-1] is not a subarray.
Constraints:
1 <= nums.length <= 2 * 104
-10 <= nums[i] <= 10
- The product of any prefix or suffix of
nums
is guaranteed to fit in a 32-bit integer.
class Solution:
def maxProduct(self, nums: List[int]) -> int:
maxf = minf = nums[0]
res, n = nums[0], len(nums)
for i in range(1, n):
p, q = maxf, minf
maxf = max(nums[i], p * nums[i], q * nums[i])
minf = min(nums[i], p * nums[i], q * nums[i])
res = max(res, maxf)
return res
class Solution {
public int maxProduct(int[] nums) {
int maxf = nums[0], minf = nums[0];
int res = nums[0], n = nums.length;
for (int i = 1; i < n; ++i) {
int p = maxf, q = minf;
maxf = Math.max(nums[i], Math.max(p * nums[i], q * nums[i]));
minf = Math.min(nums[i], Math.min(p * nums[i], q * nums[i]));
res = Math.max(res, maxf);
}
return res;
}
}