How can I have a variant that accepts any string (w/ TypeScript)?

[MarkLyck]

I have a simple variant like this:

const example = cva([], {
  variants: {
      type: {
        a: 'bg-blue-500 text-blue-600',
        b: 'bg-yellow-500 text-yellow-600',
        c: 'bg-red-500 text-red-600',
      }
  }
})

This creates a type that says variants of type MUST be a | b | c | null | undefined

but I want to be able to pass an arbitrary string, if it doesn't match any existing variant, it shouldn't do anything.

But everything I've tried I'm getting an error: Type 'string' is not assignable to type '"a" | "b" | "c" | null | undefined'.

unless I override it with as any but I'd rather not add any's to my codebase.

Is there any way to make the type for this particular variant less strong? So it can accept an arbitrary string?

[joe-bell]

Could you use as?

(arbitraryValue) => example({ type: arbitraryValue as keyof VariantProps<typeof example>['type'] })