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diff_match_patch.py
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diff_match_patch.py
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#!/usr/bin/python
"""Diff Match and Patch
Copyright 2006 Google Inc.
http://code.google.com/p/google-diff-match-patch/
Licensed under the Apache License, Version 2.0 (the "License");
you may not use this file except in compliance with the License.
You may obtain a copy of the License at
http://www.apache.org/licenses/LICENSE-2.0
Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
"""
"""Functions for diff, match and patch.
Computes the difference between two texts to create a patch.
Applies the patch onto another text, allowing for errors.
"""
__author__ = '[email protected] (Neil Fraser)'
import math
import time
import urllib
import re
class diff_match_patch:
"""Class containing the diff, match and patch methods.
Also contains the behaviour settings.
"""
def __init__(self):
"""Inits a diff_match_patch object with default settings.
Redefine these in your program to override the defaults.
"""
# Number of seconds to map a diff before giving up (0 for infinity).
self.Diff_Timeout = 1.0
# Cost of an empty edit operation in terms of edit characters.
self.Diff_EditCost = 4
# The size beyond which the double-ended diff activates.
# Double-ending is twice as fast, but less accurate.
self.Diff_DualThreshold = 32
# At what point is no match declared (0.0 = perfection, 1.0 = very loose).
self.Match_Threshold = 0.5
# How far to search for a match (0 = exact location, 1000+ = broad match).
# A match this many characters away from the expected location will add
# 1.0 to the score (0.0 is a perfect match).
self.Match_Distance = 1000
# Chunk size for context length.
self.Patch_Margin = 4
# How many bits in a number?
# Python has no maximum, thus to disable patch splitting set to 0.
# However to avoid long patches in certain pathological cases, use 32.
# Multiple short patches (using native ints) are much faster than long ones.
self.Match_MaxBits = 32
# DIFF FUNCTIONS
# The data structure representing a diff is an array of tuples:
# [(DIFF_DELETE, "Hello"), (DIFF_INSERT, "Goodbye"), (DIFF_EQUAL, " world.")]
# which means: delete "Hello", add "Goodbye" and keep " world."
DIFF_DELETE = -1
DIFF_INSERT = 1
DIFF_EQUAL = 0
def diff_main(self, text1, text2, checklines=True):
"""Find the differences between two texts. Simplifies the problem by
stripping any common prefix or suffix off the texts before diffing.
Args:
text1: Old string to be diffed.
text2: New string to be diffed.
checklines: Optional speedup flag. If present and false, then don't run
a line-level diff first to identify the changed areas.
Defaults to true, which does a faster, slightly less optimal diff.
Returns:
Array of changes.
"""
# Check for equality (speedup)
if text1 == text2:
return [(self.DIFF_EQUAL, text1)]
# Trim off common prefix (speedup)
commonlength = self.diff_commonPrefix(text1, text2)
commonprefix = text1[:commonlength]
text1 = text1[commonlength:]
text2 = text2[commonlength:]
# Trim off common suffix (speedup)
commonlength = self.diff_commonSuffix(text1, text2)
if commonlength == 0:
commonsuffix = ''
else:
commonsuffix = text1[-commonlength:]
text1 = text1[:-commonlength]
text2 = text2[:-commonlength]
# Compute the diff on the middle block
diffs = self.diff_compute(text1, text2, checklines)
# Restore the prefix and suffix
if commonprefix:
diffs[:0] = [(self.DIFF_EQUAL, commonprefix)]
if commonsuffix:
diffs.append((self.DIFF_EQUAL, commonsuffix))
self.diff_cleanupMerge(diffs)
return diffs
def diff_compute(self, text1, text2, checklines):
"""Find the differences between two texts. Assumes that the texts do not
have any common prefix or suffix.
Args:
text1: Old string to be diffed.
text2: New string to be diffed.
checklines: Speedup flag. If false, then don't run a line-level diff
first to identify the changed areas.
If true, then run a faster, slightly less optimal diff.
Returns:
Array of changes.
"""
if not text1:
# Just add some text (speedup)
return [(self.DIFF_INSERT, text2)]
if not text2:
# Just delete some text (speedup)
return [(self.DIFF_DELETE, text1)]
if len(text1) > len(text2):
(longtext, shorttext) = (text1, text2)
else:
(shorttext, longtext) = (text1, text2)
i = longtext.find(shorttext)
if i != -1:
# Shorter text is inside the longer text (speedup)
diffs = [(self.DIFF_INSERT, longtext[:i]), (self.DIFF_EQUAL, shorttext),
(self.DIFF_INSERT, longtext[i + len(shorttext):])]
# Swap insertions for deletions if diff is reversed.
if len(text1) > len(text2):
diffs[0] = (self.DIFF_DELETE, diffs[0][1])
diffs[2] = (self.DIFF_DELETE, diffs[2][1])
return diffs
longtext = shorttext = None # Garbage collect
# Check to see if the problem can be split in two.
hm = self.diff_halfMatch(text1, text2)
if hm:
# A half-match was found, sort out the return data.
(text1_a, text1_b, text2_a, text2_b, mid_common) = hm
# Send both pairs off for separate processing.
diffs_a = self.diff_main(text1_a, text2_a, checklines)
diffs_b = self.diff_main(text1_b, text2_b, checklines)
# Merge the results.
return diffs_a + [(self.DIFF_EQUAL, mid_common)] + diffs_b
# Perform a real diff.
if checklines and (len(text1) < 100 or len(text2) < 100):
checklines = False # Too trivial for the overhead.
if checklines:
# Scan the text on a line-by-line basis first.
(text1, text2, linearray) = self.diff_linesToChars(text1, text2)
diffs = self.diff_map(text1, text2)
if not diffs: # No acceptable result.
diffs = [(self.DIFF_DELETE, text1), (self.DIFF_INSERT, text2)]
if checklines:
# Convert the diff back to original text.
self.diff_charsToLines(diffs, linearray)
# Eliminate freak matches (e.g. blank lines)
self.diff_cleanupSemantic(diffs)
# Rediff any replacement blocks, this time character-by-character.
# Add a dummy entry at the end.
diffs.append((self.DIFF_EQUAL, ''))
pointer = 0
count_delete = 0
count_insert = 0
text_delete = ''
text_insert = ''
while pointer < len(diffs):
if diffs[pointer][0] == self.DIFF_INSERT:
count_insert += 1
text_insert += diffs[pointer][1]
elif diffs[pointer][0] == self.DIFF_DELETE:
count_delete += 1
text_delete += diffs[pointer][1]
elif diffs[pointer][0] == self.DIFF_EQUAL:
# Upon reaching an equality, check for prior redundancies.
if count_delete >= 1 and count_insert >= 1:
# Delete the offending records and add the merged ones.
a = self.diff_main(text_delete, text_insert, False)
diffs[pointer - count_delete - count_insert : pointer] = a
pointer = pointer - count_delete - count_insert + len(a)
count_insert = 0
count_delete = 0
text_delete = ''
text_insert = ''
pointer += 1
diffs.pop() # Remove the dummy entry at the end.
return diffs
def diff_linesToChars(self, text1, text2):
"""Split two texts into an array of strings. Reduce the texts to a string
of hashes where each Unicode character represents one line.
Args:
text1: First string.
text2: Second string.
Returns:
Three element tuple, containing the encoded text1, the encoded text2 and
the array of unique strings. The zeroth element of the array of unique
strings is intentionally blank.
"""
lineArray = [] # e.g. lineArray[4] == "Hello\n"
lineHash = {} # e.g. lineHash["Hello\n"] == 4
# "\x00" is a valid character, but various debuggers don't like it.
# So we'll insert a junk entry to avoid generating a null character.
lineArray.append('')
def diff_linesToCharsMunge(text):
"""Split a text into an array of strings. Reduce the texts to a string
of hashes where each Unicode character represents one line.
Modifies linearray and linehash through being a closure.
Args:
text: String to encode.
Returns:
Encoded string.
"""
chars = []
# Walk the text, pulling out a substring for each line.
# text.split('\n') would would temporarily double our memory footprint.
# Modifying text would create many large strings to garbage collect.
lineStart = 0
lineEnd = -1
while lineEnd < len(text) - 1:
lineEnd = text.find('\n', lineStart)
if lineEnd == -1:
lineEnd = len(text) - 1
line = text[lineStart:lineEnd + 1]
lineStart = lineEnd + 1
if line in lineHash:
chars.append(unichr(lineHash[line]))
else:
lineArray.append(line)
lineHash[line] = len(lineArray) - 1
chars.append(unichr(len(lineArray) - 1))
return "".join(chars)
chars1 = diff_linesToCharsMunge(text1)
chars2 = diff_linesToCharsMunge(text2)
return (chars1, chars2, lineArray)
def diff_charsToLines(self, diffs, lineArray):
"""Rehydrate the text in a diff from a string of line hashes to real lines
of text.
Args:
diffs: Array of diff tuples.
lineArray: Array of unique strings.
"""
for x in xrange(len(diffs)):
text = []
for char in diffs[x][1]:
text.append(lineArray[ord(char)])
diffs[x] = (diffs[x][0], "".join(text))
def diff_map(self, text1, text2):
"""Explore the intersection points between the two texts.
Args:
text1: Old string to be diffed.
text2: New string to be diffed.
Returns:
Array of diff tuples or None if no diff available.
"""
# Unlike in most languages, Python counts time in seconds.
s_end = time.time() + self.Diff_Timeout # Don't run for too long.
max_d = len(text1) + len(text2) - 1
doubleEnd = self.Diff_DualThreshold * 2 < max_d
v_map1 = []
v_map2 = []
v1 = {}
v2 = {}
v1[1] = 0
v2[1] = 0
footsteps = {}
done = False
# If the total number of characters is odd, then the front path will
# collide with the reverse path.
front = (len(text1) + len(text2)) % 2
for d in xrange(max_d):
# Bail out if timeout reached.
if self.Diff_Timeout > 0 and time.time() > s_end:
return None
# Walk the front path one step.
v_map1.append({})
for k in xrange(-d, d + 1, 2):
if k == -d or k != d and v1[k - 1] < v1[k + 1]:
x = v1[k + 1]
else:
x = v1[k - 1] + 1
y = x - k
if doubleEnd:
footstep = (x, y)
if front and footstep in footsteps:
done = True
if not front:
footsteps[footstep] = d
while (not done and x < len(text1) and y < len(text2) and
text1[x] == text2[y]):
x += 1
y += 1
if doubleEnd:
footstep = (x, y)
if front and footstep in footsteps:
done = True
if not front:
footsteps[footstep] = d
v1[k] = x
v_map1[d][(x, y)] = True
if x == len(text1) and y == len(text2):
# Reached the end in single-path mode.
return self.diff_path1(v_map1, text1, text2)
elif done:
# Front path ran over reverse path.
v_map2 = v_map2[:footsteps[footstep] + 1]
a = self.diff_path1(v_map1, text1[:x], text2[:y])
b = self.diff_path2(v_map2, text1[x:], text2[y:])
return a + b
if doubleEnd:
# Walk the reverse path one step.
v_map2.append({})
for k in xrange(-d, d + 1, 2):
if k == -d or k != d and v2[k - 1] < v2[k + 1]:
x = v2[k + 1]
else:
x = v2[k - 1] + 1
y = x - k
footstep = (len(text1) - x, len(text2) - y)
if not front and footstep in footsteps:
done = True
if front:
footsteps[footstep] = d
while (not done and x < len(text1) and y < len(text2) and
text1[-x - 1] == text2[-y - 1]):
x += 1
y += 1
footstep = (len(text1) - x, len(text2) - y)
if not front and footstep in footsteps:
done = True
if front:
footsteps[footstep] = d
v2[k] = x
v_map2[d][(x, y)] = True
if done:
# Reverse path ran over front path.
v_map1 = v_map1[:footsteps[footstep] + 1]
a = self.diff_path1(v_map1, text1[:len(text1) - x],
text2[:len(text2) - y])
b = self.diff_path2(v_map2, text1[len(text1) - x:],
text2[len(text2) - y:])
return a + b
# Number of diffs equals number of characters, no commonality at all.
return None
def diff_path1(self, v_map, text1, text2):
"""Work from the middle back to the start to determine the path.
Args:
v_map: Array of paths.
text1: Old string fragment to be diffed.
text2: New string fragment to be diffed.
Returns:
Array of diff tuples.
"""
path = []
x = len(text1)
y = len(text2)
last_op = None
for d in xrange(len(v_map) - 2, -1, -1):
while True:
if (x - 1, y) in v_map[d]:
x -= 1
if last_op == self.DIFF_DELETE:
path[0] = (self.DIFF_DELETE, text1[x] + path[0][1])
else:
path[:0] = [(self.DIFF_DELETE, text1[x])]
last_op = self.DIFF_DELETE
break
elif (x, y - 1) in v_map[d]:
y -= 1
if last_op == self.DIFF_INSERT:
path[0] = (self.DIFF_INSERT, text2[y] + path[0][1])
else:
path[:0] = [(self.DIFF_INSERT, text2[y])]
last_op = self.DIFF_INSERT
break
else:
x -= 1
y -= 1
assert text1[x] == text2[y], ("No diagonal. " +
"Can't happen. (diff_path1)")
if last_op == self.DIFF_EQUAL:
path[0] = (self.DIFF_EQUAL, text1[x] + path[0][1])
else:
path[:0] = [(self.DIFF_EQUAL, text1[x])]
last_op = self.DIFF_EQUAL
return path
def diff_path2(self, v_map, text1, text2):
"""Work from the middle back to the end to determine the path.
Args:
v_map: Array of paths.
text1: Old string fragment to be diffed.
text2: New string fragment to be diffed.
Returns:
Array of diff tuples.
"""
path = []
x = len(text1)
y = len(text2)
last_op = None
for d in xrange(len(v_map) - 2, -1, -1):
while True:
if (x - 1, y) in v_map[d]:
x -= 1
if last_op == self.DIFF_DELETE:
path[-1] = (self.DIFF_DELETE, path[-1][1] + text1[-x - 1])
else:
path.append((self.DIFF_DELETE, text1[-x - 1]))
last_op = self.DIFF_DELETE
break
elif (x, y - 1) in v_map[d]:
y -= 1
if last_op == self.DIFF_INSERT:
path[-1] = (self.DIFF_INSERT, path[-1][1] + text2[-y - 1])
else:
path.append((self.DIFF_INSERT, text2[-y - 1]))
last_op = self.DIFF_INSERT
break
else:
x -= 1
y -= 1
assert text1[-x - 1] == text2[-y - 1], ("No diagonal. " +
"Can't happen. (diff_path2)")
if last_op == self.DIFF_EQUAL:
path[-1] = (self.DIFF_EQUAL, path[-1][1] + text1[-x - 1])
else:
path.append((self.DIFF_EQUAL, text1[-x - 1]))
last_op = self.DIFF_EQUAL
return path
def diff_commonPrefix(self, text1, text2):
"""Determine the common prefix of two strings.
Args:
text1: First string.
text2: Second string.
Returns:
The number of characters common to the start of each string.
"""
# Quick check for common null cases.
if not text1 or not text2 or text1[0] != text2[0]:
return 0
# Binary search.
# Performance analysis: http://neil.fraser.name/news/2007/10/09/
pointermin = 0
pointermax = min(len(text1), len(text2))
pointermid = pointermax
pointerstart = 0
while pointermin < pointermid:
if text1[pointerstart:pointermid] == text2[pointerstart:pointermid]:
pointermin = pointermid
pointerstart = pointermin
else:
pointermax = pointermid
pointermid = int((pointermax - pointermin) / 2 + pointermin)
return pointermid
def diff_commonSuffix(self, text1, text2):
"""Determine the common suffix of two strings.
Args:
text1: First string.
text2: Second string.
Returns:
The number of characters common to the end of each string.
"""
# Quick check for common null cases.
if not text1 or not text2 or text1[-1] != text2[-1]:
return 0
# Binary search.
# Performance analysis: http://neil.fraser.name/news/2007/10/09/
pointermin = 0
pointermax = min(len(text1), len(text2))
pointermid = pointermax
pointerend = 0
while pointermin < pointermid:
if (text1[-pointermid:len(text1) - pointerend] ==
text2[-pointermid:len(text2) - pointerend]):
pointermin = pointermid
pointerend = pointermin
else:
pointermax = pointermid
pointermid = int((pointermax - pointermin) / 2 + pointermin)
return pointermid
def diff_halfMatch(self, text1, text2):
"""Do the two texts share a substring which is at least half the length of
the longer text?
Args:
text1: First string.
text2: Second string.
Returns:
Five element Array, containing the prefix of text1, the suffix of text1,
the prefix of text2, the suffix of text2 and the common middle. Or None
if there was no match.
"""
if len(text1) > len(text2):
(longtext, shorttext) = (text1, text2)
else:
(shorttext, longtext) = (text1, text2)
if len(longtext) < 10 or len(shorttext) < 1:
return None # Pointless.
def diff_halfMatchI(longtext, shorttext, i):
"""Does a substring of shorttext exist within longtext such that the
substring is at least half the length of longtext?
Closure, but does not reference any external variables.
Args:
longtext: Longer string.
shorttext: Shorter string.
i: Start index of quarter length substring within longtext.
Returns:
Five element Array, containing the prefix of longtext, the suffix of
longtext, the prefix of shorttext, the suffix of shorttext and the
common middle. Or None if there was no match.
"""
seed = longtext[i:i + len(longtext) / 4]
best_common = ''
j = shorttext.find(seed)
while j != -1:
prefixLength = self.diff_commonPrefix(longtext[i:], shorttext[j:])
suffixLength = self.diff_commonSuffix(longtext[:i], shorttext[:j])
if len(best_common) < suffixLength + prefixLength:
best_common = (shorttext[j - suffixLength:j] +
shorttext[j:j + prefixLength])
best_longtext_a = longtext[:i - suffixLength]
best_longtext_b = longtext[i + prefixLength:]
best_shorttext_a = shorttext[:j - suffixLength]
best_shorttext_b = shorttext[j + prefixLength:]
j = shorttext.find(seed, j + 1)
if len(best_common) >= len(longtext) / 2:
return (best_longtext_a, best_longtext_b,
best_shorttext_a, best_shorttext_b, best_common)
else:
return None
# First check if the second quarter is the seed for a half-match.
hm1 = diff_halfMatchI(longtext, shorttext, (len(longtext) + 3) / 4)
# Check again based on the third quarter.
hm2 = diff_halfMatchI(longtext, shorttext, (len(longtext) + 1) / 2)
if not hm1 and not hm2:
return None
elif not hm2:
hm = hm1
elif not hm1:
hm = hm2
else:
# Both matched. Select the longest.
if len(hm1[4]) > len(hm2[4]):
hm = hm1
else:
hm = hm2
# A half-match was found, sort out the return data.
if len(text1) > len(text2):
(text1_a, text1_b, text2_a, text2_b, mid_common) = hm
else:
(text2_a, text2_b, text1_a, text1_b, mid_common) = hm
return (text1_a, text1_b, text2_a, text2_b, mid_common)
def diff_cleanupSemantic(self, diffs):
"""Reduce the number of edits by eliminating semantically trivial
equalities.
Args:
diffs: Array of diff tuples.
"""
changes = False
equalities = [] # Stack of indices where equalities are found.
lastequality = None # Always equal to equalities[-1][1]
pointer = 0 # Index of current position.
length_changes1 = 0 # Number of chars that changed prior to the equality.
length_changes2 = 0 # Number of chars that changed after the equality.
while pointer < len(diffs):
if diffs[pointer][0] == self.DIFF_EQUAL: # equality found
equalities.append(pointer)
length_changes1 = length_changes2
length_changes2 = 0
lastequality = diffs[pointer][1]
else: # an insertion or deletion
length_changes2 += len(diffs[pointer][1])
if (lastequality != None and (len(lastequality) <= length_changes1) and
(len(lastequality) <= length_changes2)):
# Duplicate record
diffs.insert(equalities[-1], (self.DIFF_DELETE, lastequality))
# Change second copy to insert.
diffs[equalities[-1] + 1] = (self.DIFF_INSERT,
diffs[equalities[-1] + 1][1])
# Throw away the equality we just deleted.
equalities.pop()
# Throw away the previous equality (it needs to be reevaluated).
if len(equalities) != 0:
equalities.pop()
if len(equalities):
pointer = equalities[-1]
else:
pointer = -1
length_changes1 = 0 # Reset the counters.
length_changes2 = 0
lastequality = None
changes = True
pointer += 1
if changes:
self.diff_cleanupMerge(diffs)
self.diff_cleanupSemanticLossless(diffs)
def diff_cleanupSemanticLossless(self, diffs):
"""Look for single edits surrounded on both sides by equalities
which can be shifted sideways to align the edit to a word boundary.
e.g: The c<ins>at c</ins>ame. -> The <ins>cat </ins>came.
Args:
diffs: Array of diff tuples.
"""
def diff_cleanupSemanticScore(one, two):
"""Given two strings, compute a score representing whether the
internal boundary falls on logical boundaries.
Scores range from 5 (best) to 0 (worst).
Closure, but does not reference any external variables.
Args:
one: First string.
two: Second string.
Returns:
The score.
"""
if not one or not two:
# Edges are the best.
return 5
# Each port of this function behaves slightly differently due to
# subtle differences in each language's definition of things like
# 'whitespace'. Since this function's purpose is largely cosmetic,
# the choice has been made to use each language's native features
# rather than force total conformity.
score = 0
# One point for non-alphanumeric.
if not one[-1].isalnum() or not two[0].isalnum():
score += 1
# Two points for whitespace.
if one[-1].isspace() or two[0].isspace():
score += 1
# Three points for line breaks.
if (one[-1] == "\r" or one[-1] == "\n" or
two[0] == "\r" or two[0] == "\n"):
score += 1
# Four points for blank lines.
if (re.search("\\n\\r?\\n$", one) or
re.match("^\\r?\\n\\r?\\n", two)):
score += 1
return score
pointer = 1
# Intentionally ignore the first and last element (don't need checking).
while pointer < len(diffs) - 1:
if (diffs[pointer - 1][0] == self.DIFF_EQUAL and
diffs[pointer + 1][0] == self.DIFF_EQUAL):
# This is a single edit surrounded by equalities.
equality1 = diffs[pointer - 1][1]
edit = diffs[pointer][1]
equality2 = diffs[pointer + 1][1]
# First, shift the edit as far left as possible.
commonOffset = self.diff_commonSuffix(equality1, edit)
if commonOffset:
commonString = edit[-commonOffset:]
equality1 = equality1[:-commonOffset]
edit = commonString + edit[:-commonOffset]
equality2 = commonString + equality2
# Second, step character by character right, looking for the best fit.
bestEquality1 = equality1
bestEdit = edit
bestEquality2 = equality2
bestScore = (diff_cleanupSemanticScore(equality1, edit) +
diff_cleanupSemanticScore(edit, equality2))
while edit and equality2 and edit[0] == equality2[0]:
equality1 += edit[0]
edit = edit[1:] + equality2[0]
equality2 = equality2[1:]
score = (diff_cleanupSemanticScore(equality1, edit) +
diff_cleanupSemanticScore(edit, equality2))
# The >= encourages trailing rather than leading whitespace on edits.
if score >= bestScore:
bestScore = score
bestEquality1 = equality1
bestEdit = edit
bestEquality2 = equality2
if diffs[pointer - 1][1] != bestEquality1:
# We have an improvement, save it back to the diff.
if bestEquality1:
diffs[pointer - 1] = (diffs[pointer - 1][0], bestEquality1)
else:
del diffs[pointer - 1]
pointer -= 1
diffs[pointer] = (diffs[pointer][0], bestEdit)
if bestEquality2:
diffs[pointer + 1] = (diffs[pointer + 1][0], bestEquality2)
else:
del diffs[pointer + 1]
pointer -= 1
pointer += 1
def diff_cleanupEfficiency(self, diffs):
"""Reduce the number of edits by eliminating operationally trivial
equalities.
Args:
diffs: Array of diff tuples.
"""
changes = False
equalities = [] # Stack of indices where equalities are found.
lastequality = '' # Always equal to equalities[-1][1]
pointer = 0 # Index of current position.
pre_ins = False # Is there an insertion operation before the last equality.
pre_del = False # Is there a deletion operation before the last equality.
post_ins = False # Is there an insertion operation after the last equality.
post_del = False # Is there a deletion operation after the last equality.
while pointer < len(diffs):
if diffs[pointer][0] == self.DIFF_EQUAL: # equality found
if (len(diffs[pointer][1]) < self.Diff_EditCost and
(post_ins or post_del)):
# Candidate found.
equalities.append(pointer)
pre_ins = post_ins
pre_del = post_del
lastequality = diffs[pointer][1]
else:
# Not a candidate, and can never become one.
equalities = []
lastequality = ''
post_ins = post_del = False
else: # an insertion or deletion
if diffs[pointer][0] == self.DIFF_DELETE:
post_del = True
else:
post_ins = True
# Five types to be split:
# <ins>A</ins><del>B</del>XY<ins>C</ins><del>D</del>
# <ins>A</ins>X<ins>C</ins><del>D</del>
# <ins>A</ins><del>B</del>X<ins>C</ins>
# <ins>A</del>X<ins>C</ins><del>D</del>
# <ins>A</ins><del>B</del>X<del>C</del>
if lastequality and ((pre_ins and pre_del and post_ins and post_del) or
((len(lastequality) < self.Diff_EditCost / 2) and
(pre_ins + pre_del + post_ins + post_del) == 3)):
# Duplicate record
diffs.insert(equalities[-1], (self.DIFF_DELETE, lastequality))
# Change second copy to insert.
diffs[equalities[-1] + 1] = (self.DIFF_INSERT,
diffs[equalities[-1] + 1][1])
equalities.pop() # Throw away the equality we just deleted
lastequality = ''
if pre_ins and pre_del:
# No changes made which could affect previous entry, keep going.
post_ins = post_del = True
equalities = []
else:
if len(equalities):
equalities.pop() # Throw away the previous equality
if len(equalities):
pointer = equalities[-1]
else:
pointer = -1
post_ins = post_del = False
changes = True
pointer += 1
if changes:
self.diff_cleanupMerge(diffs)
def diff_cleanupMerge(self, diffs):
"""Reorder and merge like edit sections. Merge equalities.
Any edit section can move as long as it doesn't cross an equality.
Args:
diffs: Array of diff tuples.
"""
diffs.append((self.DIFF_EQUAL, '')) # Add a dummy entry at the end.
pointer = 0
count_delete = 0
count_insert = 0
text_delete = ''
text_insert = ''
while pointer < len(diffs):
if diffs[pointer][0] == self.DIFF_INSERT:
count_insert += 1
text_insert += diffs[pointer][1]
pointer += 1
elif diffs[pointer][0] == self.DIFF_DELETE:
count_delete += 1
text_delete += diffs[pointer][1]
pointer += 1
elif diffs[pointer][0] == self.DIFF_EQUAL:
# Upon reaching an equality, check for prior redundancies.
if count_delete != 0 or count_insert != 0:
if count_delete != 0 and count_insert != 0:
# Factor out any common prefixies.
commonlength = self.diff_commonPrefix(text_insert, text_delete)
if commonlength != 0:
x = pointer - count_delete - count_insert - 1
if x >= 0 and diffs[x][0] == self.DIFF_EQUAL:
diffs[x] = (diffs[x][0], diffs[x][1] +
text_insert[:commonlength])
else:
diffs.insert(0, (self.DIFF_EQUAL, text_insert[:commonlength]))
pointer += 1
text_insert = text_insert[commonlength:]
text_delete = text_delete[commonlength:]
# Factor out any common suffixies.
commonlength = self.diff_commonSuffix(text_insert, text_delete)
if commonlength != 0:
diffs[pointer] = (diffs[pointer][0], text_insert[-commonlength:] +
diffs[pointer][1])
text_insert = text_insert[:-commonlength]
text_delete = text_delete[:-commonlength]
# Delete the offending records and add the merged ones.
if count_delete == 0:
diffs[pointer - count_insert : pointer] = [
(self.DIFF_INSERT, text_insert)]
elif count_insert == 0:
diffs[pointer - count_delete : pointer] = [
(self.DIFF_DELETE, text_delete)]
else:
diffs[pointer - count_delete - count_insert : pointer] = [
(self.DIFF_DELETE, text_delete),
(self.DIFF_INSERT, text_insert)]
pointer = pointer - count_delete - count_insert + 1
if count_delete != 0:
pointer += 1
if count_insert != 0:
pointer += 1
elif pointer != 0 and diffs[pointer - 1][0] == self.DIFF_EQUAL:
# Merge this equality with the previous one.
diffs[pointer - 1] = (diffs[pointer - 1][0],
diffs[pointer - 1][1] + diffs[pointer][1])
del diffs[pointer]
else:
pointer += 1
count_insert = 0
count_delete = 0
text_delete = ''
text_insert = ''
if diffs[-1][1] == '':
diffs.pop() # Remove the dummy entry at the end.
# Second pass: look for single edits surrounded on both sides by equalities
# which can be shifted sideways to eliminate an equality.
# e.g: A<ins>BA</ins>C -> <ins>AB</ins>AC
changes = False
pointer = 1
# Intentionally ignore the first and last element (don't need checking).
while pointer < len(diffs) - 1:
if (diffs[pointer - 1][0] == self.DIFF_EQUAL and
diffs[pointer + 1][0] == self.DIFF_EQUAL):
# This is a single edit surrounded by equalities.
if diffs[pointer][1].endswith(diffs[pointer - 1][1]):
# Shift the edit over the previous equality.
diffs[pointer] = (diffs[pointer][0],
diffs[pointer - 1][1] +
diffs[pointer][1][:-len(diffs[pointer - 1][1])])
diffs[pointer + 1] = (diffs[pointer + 1][0],
diffs[pointer - 1][1] + diffs[pointer + 1][1])
del diffs[pointer - 1]
changes = True
elif diffs[pointer][1].startswith(diffs[pointer + 1][1]):
# Shift the edit over the next equality.
diffs[pointer - 1] = (diffs[pointer - 1][0],
diffs[pointer - 1][1] + diffs[pointer + 1][1])
diffs[pointer] = (diffs[pointer][0],
diffs[pointer][1][len(diffs[pointer + 1][1]):] +
diffs[pointer + 1][1])
del diffs[pointer + 1]
changes = True
pointer += 1
# If shifts were made, the diff needs reordering and another shift sweep.
if changes:
self.diff_cleanupMerge(diffs)
def diff_xIndex(self, diffs, loc):
"""loc is a location in text1, compute and return the equivalent location
in text2. e.g. "The cat" vs "The big cat", 1->1, 5->8
Args:
diffs: Array of diff tuples.
loc: Location within text1.
Returns:
Location within text2.
"""
chars1 = 0
chars2 = 0
last_chars1 = 0
last_chars2 = 0
for x in xrange(len(diffs)):
(op, text) = diffs[x]
if op != self.DIFF_INSERT: # Equality or deletion.
chars1 += len(text)
if op != self.DIFF_DELETE: # Equality or insertion.
chars2 += len(text)
if chars1 > loc: # Overshot the location.
break
last_chars1 = chars1
last_chars2 = chars2
if len(diffs) != x and diffs[x][0] == self.DIFF_DELETE:
# The location was deleted.
return last_chars2
# Add the remaining len(character).
return last_chars2 + (loc - last_chars1)
def diff_prettyHtml(self, diffs):
"""Convert a diff array into a pretty HTML report.
Args:
diffs: Array of diff tuples.
Returns:
HTML representation.
"""
html = []
i = 0
for (op, data) in diffs:
text = (data.replace("&", "&").replace("<", "<")
.replace(">", ">").replace("\n", "¶<BR>"))
if op == self.DIFF_INSERT:
html.append("<INS STYLE=\"background:#E6FFE6;\" TITLE=\"i=%i\">%s</INS>"
% (i, text))