The number of arguments which will be passed into a function.
I don't know.
The name of the program.
[see picture of process / memory organisation struct from mit xv6]
Yes, in perl $0
is also the name of the program.
[ruby example?]
An array (=equal-length boxes stacked N
long) containing the arguments
which will be passed to the function.
Then instead of {{type}} name[size]
, write {{type}} name[]
.
#includes
//globals
//possibly functions
int main(int argc, char* argv[])
{
//the program
return(0);
}
//maybe more functions
[xv6 answer]
No, it's not a mathematical function. Computer people just like to mis-use maths words to intimidate you.
The instructions sit in a plain text file. You need to "build" them into a program. Building them requires a lexer+tokenizer to scan the text, a compiler to turn the parsed text into something closer to computer instructions, and a linker (man ld
, man ar
, man nm
) to bring stuff from various places (like #include <graphics.h>
or #include <tty.h>
) into the executable you're building.
This multi-step process might be driven by a Makefile
. make
is a scripting language with a horrendously long manual which nobody actually likes but which does the job of scanning for requirements and dependencies and then executing instructions only if a job actually needs to be done.
It makes the job of scanning and tokenising your text instructions easier. If you didn't terminate a line with ;
then the person writing the compiler would have to infer what you almost certainly meant (but remember, they wrote the compiler without talking to you or looking at your code).