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I would expect that joinPath[a,b] behaves exactly like a </> b (aka combine a b). Unfortunately, the documentation does not enlighten me on the relationship between joinPath and combine. Is joinPath just a fold using the monoid mempty = ""; mappend = combine?
I would have consulted the source code to clarify my question, but see #81.
Please document the relationship between joinPath and combine.
The text was updated successfully, but these errors were encountered:
Perfectly reasonable, and also your remark about sources in #81. Note the library is transitioning ownership through #79, so I will wait for the next maintainer to respond properly.
I would expect that
joinPath[a,b]
behaves exactly likea </> b
(akacombine a b
). Unfortunately, the documentation does not enlighten me on the relationship betweenjoinPath
andcombine
. IsjoinPath
just a fold using the monoidmempty = ""; mappend = combine
?I would have consulted the source code to clarify my question, but see #81.
Please document the relationship between
joinPath
andcombine
.The text was updated successfully, but these errors were encountered: