Given a reference of a node in a connected undirected graph.
Return a deep copy (clone) of the graph.
Each node in the graph contains a val (int
) and a list (List[Node]
) of its neighbors.
class Node {
public int val;
public List<Node> neighbors;
}
For simplicity sake, each node's value is the same as the node's index (1-indexed). For example, the first node with val = 1
, the second node with val = 2
, and so on. The graph is represented in the test case using an adjacency list.
Adjacency list is a collection of unordered lists used to represent a finite graph. Each list describes the set of neighbors of a node in the graph.
The given node will always be the first node with val = 1
. You must return the copy of the given node as a reference to the cloned graph.
Input: adjList = [[2,4],[1,3],[2,4],[1,3]] Output: [[2,4],[1,3],[2,4],[1,3]] Explanation: There are 4 nodes in the graph. 1st node (val = 1)'s neighbors are 2nd node (val = 2) and 4th node (val = 4). 2nd node (val = 2)'s neighbors are 1st node (val = 1) and 3rd node (val = 3). 3rd node (val = 3)'s neighbors are 2nd node (val = 2) and 4th node (val = 4). 4th node (val = 4)'s neighbors are 1st node (val = 1) and 3rd node (val = 3).
Input: adjList = [[]] Output: [[]] Explanation: Note that the input contains one empty list. The graph consists of only one node with val = 1 and it does not have any neighbors.
Input: adjList = [] Output: [] Explanation: This an empty graph, it does not have any nodes.
Input: adjList = [[2],[1]] Output: [[2],[1]]
1 <= Node.val <= 100
Node.val
is unique for each node.- Number of Nodes will not exceed 100.
- There is no repeated edges and no self-loops in the graph.
- The Graph is connected and all nodes can be visited starting from the given node.
"""
# Definition for a Node.
class Node:
def __init__(self, val = 0, neighbors = None):
self.val = val
self.neighbors = neighbors if neighbors is not None else []
"""
class Solution:
def cloneGraph(self, node: 'Node') -> 'Node':
if not node:
return None
nodes = [node]
visited = [False] * 101
visited[node.val] = True
i = 0
while i < len(nodes):
node = nodes[i]
for neighbor in node.neighbors:
if not visited[neighbor.val]:
visited[neighbor.val] = True
nodes.append(neighbor)
node.neighbors.append(Node(node.val))
i += 1
for node in nodes:
copy = node.neighbors[-1]
for neighbor in node.neighbors[:-1]:
copy.neighbors.append(neighbor.neighbors[-1])
copy = nodes[0].neighbors[-1]
for node in nodes:
node.neighbors.pop()
return copy