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I don't know what the S K definition of this is:
B3 = a => b => c => d => a(b(c(d)))
The text was updated successfully, but these errors were encountered:
The Becard (B3) combinator is equivalent to the following in SK combinatorics:
((S(K((S(K((S(KS))K)))((S(KS))K))))((S(KS))K))
You can simplify this by using the Bluebird combinator (B):
((S(KS))K)
Then B3 is definable as:
B(BB)B
This is a good reference that I use for looking up such things from time to time: Angelfire Combinator Birds Reference.
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I don't know what the S K definition of this is:
The text was updated successfully, but these errors were encountered: