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knuth_morris_pratt.py
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knuth_morris_pratt.py
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from __future__ import annotations
def knuth_morris_pratt(text: str, pattern: str) -> int:
"""
The Knuth-Morris-Pratt Algorithm for finding a pattern within a piece of text
with complexity O(n + m)
1) Preprocess pattern to identify any suffixes that are identical to prefixes
This tells us where to continue from if we get a mismatch between a character
in our pattern and the text.
2) Step through the text one character at a time and compare it to a character in
the pattern updating our location within the pattern if necessary
>>> kmp = "knuth_morris_pratt"
>>> all(
... knuth_morris_pratt(kmp, s) == kmp.find(s)
... for s in ("kn", "h_m", "rr", "tt", "not there")
... )
True
"""
# 1) Construct the failure array
failure = get_failure_array(pattern)
# 2) Step through text searching for pattern
i, j = 0, 0 # index into text, pattern
while i < len(text):
if pattern[j] == text[i]:
if j == (len(pattern) - 1):
return i - j
j += 1
# if this is a prefix in our pattern
# just go back far enough to continue
elif j > 0:
j = failure[j - 1]
continue
i += 1
return -1
def get_failure_array(pattern: str) -> list[int]:
"""
Calculates the new index we should go to if we fail a comparison
:param pattern:
:return:
"""
failure = [0]
i = 0
j = 1
while j < len(pattern):
if pattern[i] == pattern[j]:
i += 1
elif i > 0:
i = failure[i - 1]
continue
j += 1
failure.append(i)
return failure
if __name__ == "__main__":
import doctest
doctest.testmod()
# Test 1)
pattern = "abc1abc12"
text1 = "alskfjaldsabc1abc1abc12k23adsfabcabc"
text2 = "alskfjaldsk23adsfabcabc"
assert knuth_morris_pratt(text1, pattern)
assert knuth_morris_pratt(text2, pattern)
# Test 2)
pattern = "ABABX"
text = "ABABZABABYABABX"
assert knuth_morris_pratt(text, pattern)
# Test 3)
pattern = "AAAB"
text = "ABAAAAAB"
assert knuth_morris_pratt(text, pattern)
# Test 4)
pattern = "abcdabcy"
text = "abcxabcdabxabcdabcdabcy"
assert knuth_morris_pratt(text, pattern)
# Test 5) -> Doctests
kmp = "knuth_morris_pratt"
assert all(
knuth_morris_pratt(kmp, s) == kmp.find(s)
for s in ("kn", "h_m", "rr", "tt", "not there")
)
# Test 6)
pattern = "aabaabaaa"
assert get_failure_array(pattern) == [0, 1, 0, 1, 2, 3, 4, 5, 2]