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snap_scan.py
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snap_scan.py
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import cv2
import datetime
import os
import time
import imutils
import numpy as np
def four_point_transform(image, pts):
# obtain a consistent order of the points and unpack them
# individually
rect = order_points(pts)
(tl, tr, br, bl) = rect
# compute the width of the new image, which will be the
# maximum distance between bottom-right and bottom-left
# x-coordiates or the top-right and top-left x-coordinates
widthA = np.sqrt(((br[0] - bl[0]) ** 2) + ((br[1] - bl[1]) ** 2))
widthB = np.sqrt(((tr[0] - tl[0]) ** 2) + ((tr[1] - tl[1]) ** 2))
maxWidth = max(int(widthA), int(widthB))
# compute the height of the new image, which will be the
# maximum distance between the top-right and bottom-right
# y-coordinates or the top-left and bottom-left y-coordinates
heightA = np.sqrt(((tr[0] - br[0]) ** 2) + ((tr[1] - br[1]) ** 2))
heightB = np.sqrt(((tl[0] - bl[0]) ** 2) + ((tl[1] - bl[1]) ** 2))
maxHeight = max(int(heightA), int(heightB))
# now that we have the dimensions of the new image, construct
# the set of destination points to obtain a "birds eye view",
# (i.e. top-down view) of the image, again specifying points
# in the top-left, top-right, bottom-right, and bottom-left
# order
dst = np.array([
[0, 0],
[maxWidth - 1, 0],
[maxWidth - 1, maxHeight - 1],
[0, maxHeight - 1]], dtype = "float32")
# compute the perspective transform matrix and then apply it
M = cv2.getPerspectiveTransform(rect, dst)
warped = cv2.warpPerspective(image, M, (maxWidth, maxHeight))
# return the warped image
return warped
def order_points(pts):
# initialzie a list of coordinates that will be ordered
# such that the first entry in the list is the top-left,
# the second entry is the top-right, the third is the
# bottom-right, and the fourth is the bottom-left
rect = np.zeros((4, 2), dtype = "float32")
# the top-left point will have the smallest sum, whereas
# the bottom-right point will have the largest sum
s = pts.sum(axis = 1)
rect[0] = pts[np.argmin(s)]
rect[2] = pts[np.argmax(s)]
# now, compute the difference between the points, the
# top-right point will have the smallest difference,
# whereas the bottom-left will have the largest difference
diff = np.diff(pts, axis = 1)
rect[1] = pts[np.argmin(diff)]
rect[3] = pts[np.argmax(diff)]
# return the ordered coordinates
return rect
def nothing(x):
pass
now= datetime.datetime.now()
date= str(now.year)+"-"+str(now.month)+"-"+str(now.day)+"-"+str(now.hour)+"-"+str(now.minute)+"-"+str(now.second)
dir="Snapshot "+ date
cap = cv2.VideoCapture(2)
def set720p():
cap.set(3, 1280)
cap.set(4, 720)
return
def set480p():
cap.set(3, 640)
cap.set(4, 480)
def set1080p():
cap.set(3, 1920)
cap.set(4, 1080)
i=1
newdir=False
set1080p()
while(1):
ret, frame = cap.read()
ratio = frame.shape[0] / 500.0
orig = frame.copy()
frame = imutils.resize(frame, height = 500)
gray = cv2.cvtColor(frame, cv2.COLOR_BGR2GRAY)
gray = cv2.GaussianBlur(gray, (5, 5), 0)
edged = cv2.Canny(gray, 0, 100)
cv2.imshow("Edged", edged)
cnts = cv2.findContours(edged.copy(), cv2.RETR_LIST, cv2.CHAIN_APPROX_SIMPLE)
cnts = imutils.grab_contours(cnts)
cnts = sorted(cnts, key = cv2.contourArea, reverse = True)[:5]
for c in cnts:
# approximate the contour
peri = cv2.arcLength(c, True)
approx = cv2.approxPolyDP(c, 0.02 * peri, True)
# if our approximated contour has four points, then we
# can assume that we have found our screen
if len(approx) == 4:
screenCnt = approx
break
cv2.drawContours(frame, [screenCnt], -1, (0, 255, 0), 2)
cv2.imshow("Outline", frame)
k = cv2.waitKey(1)
if k == 27:
cap.release()
break
elif k==32:
if newdir==False:
os.mkdir(dir)
os.chdir(dir)
newdir=True
# FileName='Snapshot '+str(i)+'.png'
# cv2.imwrite(FileName, frame)
warped = four_point_transform(orig, screenCnt.reshape(4, 2) * ratio)
FileName2='Snapshot '+str(i)+'.jpg'
cv2.imwrite(FileName2, warped)
print("Image "+str(i)+" written")
cv2.imshow("Image "+str(i),warped)
i+=1
cv2.destroyAllWindows()