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best solution there i could find is: 0 0 1-7,15-21 * 2, which however fails as soon as a month has three biweekly days (eg monday or tuesday in december 2024)
i still believe the better way to go is to have a weekly cron, with logic in the python that checks if it already ran last week or not
Yeah I think you're right. Wasn't thinking a day showing up 5 times in a week.
I can't recall the code I did it in, but thinking about it more, I just ran weekly, then took the week number and continued without doing anything if it was even. Let me know if you want me to find a code example.
waiting on mimic to come up with a final deadline every epoch, so we know that the report is ready
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