Module2Lesson2CS.py

# Decisions at the Crossroad
# Task 1: Code Correction - You are provided with a Python script that uses conditional statements to tell if a number is positive, negative, or zero, but it has some errors. Identify and fix them.

number1 = int(input("Enter a number: "))

if number1 > 0:
    print("The number is positive.")
elif number1 == 0:
    print("The number is zero.")
else:
    print("The number is negative.")

number2 = int(input("Enter a number: "))

if number2 > 0:
    print("The number is positive.")
elif number2 == 0:
    print("The number is zero.")
else:
    print("The number is negative.")

number3 = int(input("Enter a number: "))

if number3 > 0:
    print("The number is positive.")
elif number3 == 0:
    print("The number is zero.")
else:
    print("The number is negative.")

# The Greatest Showdown
# Task 1: Identify the Greatest - Write a Python program that asks the user to enter three numbers. Your code should then identify and print out the largest number among the three.
# Task 2: Identify the Smallest- Improve upon your code from Task 1 to also determine the smallest number among the three and print it out.
# Expected Outcome: If we provide the numbers 3, 3, and 4, it should print out that "The smallest number is 3. The largest number is 4. "

number1 = int(input("Please enter a number (0-9): "))
number2 = int(input("Please enter a number (0-9): "))
number3 = int(input("Please enter a number (0-9): "))

if number1 >= number2 and number1 >= number3:
  print(f"The largest number is {number1}")
elif number2 >= number1 and number2 >= number3:
  print(f"The largest number is {number2}")
else:
  print(f"The largest number is {number3}")

if number1 <= number2 and number1 <= number3:
  print(f"The smallest number is {number1}")
elif number2 <= number1 and number2 <= number3:
  print(f"The smallest number is {number2}")
else:
  print(f"The smallest number is {number3}")

# Leap Year Explorer
# Leap Year Checker - Write a Python program that prompts the user to input a year. The program should determine if the given year is a leap year or not and then display an appropriate message.
# Please note that this is the definition of a leap year: Every year that is exactly divisible by four is a leap year, except for years that are exactly divisible by 100, but these centurial years are leap years if they are exactly divisible by 400.
# Expected Outcome: If you test the year 1900, it should be False. The year 2000 should be True. The year 2024 should be True

year = int(input("Please enter the year with 4 digits: "))

if year % 400 == 0:
  print("True")
elif year % 100 == 0:
  print("False")
elif year % 4 == 0:
  print("True")
else:
  print("False")