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困难
数据库

1479. 周内每天的销售情况 🔒

English Version

题目描述

表：Orders

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| order_id      | int     |
| customer_id   | int     |
| order_date    | date    | 
| item_id       | varchar |
| quantity      | int     |
+---------------+---------+
(order_id, item_id) 是该表主键(具有唯一值的列的组合)
该表包含了订单信息
order_date 是id为 item_id 的商品被id为 customer_id 的消费者订购的日期.

表：Items

+---------------------+---------+
| Column Name         | Type    |
+---------------------+---------+
| item_id             | varchar |
| item_name           | varchar |
| item_category       | varchar |
+---------------------+---------+
item_id 是该表主键(具有唯一值的列)
item_name 是商品的名字
item_category 是商品的类别

 

你是企业主，想要获得分类商品和周内每天的销售报告。

编写解决方案，报告 周内每天 每个商品类别下订购了多少单位。

返回结果表单 按商品类别排序 。

结果格式如下例所示。

 

示例 1：

输入：
Orders 表：
+------------+--------------+-------------+--------------+-------------+
| order_id   | customer_id  | order_date  | item_id      | quantity    |
+------------+--------------+-------------+--------------+-------------+
| 1          | 1            | 2020-06-01  | 1            | 10          |
| 2          | 1            | 2020-06-08  | 2            | 10          |
| 3          | 2            | 2020-06-02  | 1            | 5           |
| 4          | 3            | 2020-06-03  | 3            | 5           |
| 5          | 4            | 2020-06-04  | 4            | 1           |
| 6          | 4            | 2020-06-05  | 5            | 5           |
| 7          | 5            | 2020-06-05  | 1            | 10          |
| 8          | 5            | 2020-06-14  | 4            | 5           |
| 9          | 5            | 2020-06-21  | 3            | 5           |
+------------+--------------+-------------+--------------+-------------+

Items 表：
+------------+----------------+---------------+
| item_id    | item_name      | item_category |
+------------+----------------+---------------+
| 1          | LC Alg. Book   | Book          |
| 2          | LC DB. Book    | Book          |
| 3          | LC SmarthPhone | Phone         |
| 4          | LC Phone 2020  | Phone         |
| 5          | LC SmartGlass  | Glasses       |
| 6          | LC T-Shirt XL  | T-Shirt       |
+------------+----------------+---------------+
输出：
+------------+-----------+-----------+-----------+-----------+-----------+-----------+-----------+
| Category   | Monday    | Tuesday   | Wednesday | Thursday  | Friday    | Saturday  | Sunday    |
+------------+-----------+-----------+-----------+-----------+-----------+-----------+-----------+
| Book       | 20        | 5         | 0         | 0         | 10        | 0         | 0         |
| Glasses    | 0         | 0         | 0         | 0         | 5         | 0         | 0         |
| Phone      | 0         | 0         | 5         | 1         | 0         | 0         | 10        |
| T-Shirt    | 0         | 0         | 0         | 0         | 0         | 0         | 0         |
+------------+-----------+-----------+-----------+-----------+-----------+-----------+-----------+
解释：
在周一(2020-06-01, 2020-06-08)，Book分类(ids: 1, 2)下，总共销售了20个单位(10 + 10)
在周二(2020-06-02)，Book分类(ids: 1, 2)下，总共销售了5个单位
在周三(2020-06-03)，Phone分类(ids: 3, 4)下，总共销售了5个单位
在周四(2020-06-04)，Phone分类(ids: 3, 4)下，总共销售了1个单位
在周五(2020-06-05)，Book分类(ids: 1, 2)下，总共销售了10个单位，Glasses分类(ids: 5)下，总共销售了5个单位
在周六, 没有商品销售
在周天(2020-06-14, 2020-06-21)，Phone分类(ids: 3, 4)下，总共销售了10个单位(5 + 5)
没有销售 T-Shirt 类别的商品

解法

方法一

MySQL

# Write your MySQL query statement below
SELECT
    item_category AS category,
    SUM(IF(DAYOFWEEK(order_date) = '2', quantity, 0)) AS Monday,
    SUM(IF(DAYOFWEEK(order_date) = '3', quantity, 0)) AS Tuesday,
    SUM(IF(DAYOFWEEK(order_date) = '4', quantity, 0)) AS Wednesday,
    SUM(IF(DAYOFWEEK(order_date) = '5', quantity, 0)) AS Thursday,
    SUM(IF(DAYOFWEEK(order_date) = '6', quantity, 0)) AS Friday,
    SUM(IF(DAYOFWEEK(order_date) = '7', quantity, 0)) AS Saturday,
    SUM(IF(DAYOFWEEK(order_date) = '1', quantity, 0)) AS Sunday
FROM
    Orders AS o
    RIGHT JOIN Items AS i ON o.item_id = i.item_id
GROUP BY category
ORDER BY category;