README_EN.md

comments	difficulty	edit_url	rating	source	tags
true	Medium	https://github.com/doocs/leetcode/edit/main/solution/1200-1299/1291.Sequential%20Digits/README_EN.md	1373	Weekly Contest 167 Q2	Enumeration

1291. Sequential Digits

中文文档

Description

An integer has sequential digits if and only if each digit in the number is one more than the previous digit.

Return a sorted list of all the integers in the range [low, high] inclusive that have sequential digits.

 

Example 1:

Input: low = 100, high = 300
Output: [123,234]

Example 2:

Input: low = 1000, high = 13000
Output: [1234,2345,3456,4567,5678,6789,12345]

 

Constraints:

• 10 <= low <= high <= 10^9

Solutions

Solution 1

Python3

class Solution:
    def sequentialDigits(self, low: int, high: int) -> List[int]:
        ans = []
        for i in range(1, 9):
            x = i
            for j in range(i + 1, 10):
                x = x * 10 + j
                if low <= x <= high:
                    ans.append(x)
        return sorted(ans)

Java

class Solution {
    public List<Integer> sequentialDigits(int low, int high) {
        List<Integer> ans = new ArrayList<>();
        for (int i = 1; i < 9; ++i) {
            int x = i;
            for (int j = i + 1; j < 10; ++j) {
                x = x * 10 + j;
                if (x >= low && x <= high) {
                    ans.add(x);
                }
            }
        }
        Collections.sort(ans);
        return ans;
    }
}

C++

class Solution {
public:
    vector<int> sequentialDigits(int low, int high) {
        vector<int> ans;
        for (int i = 1; i < 9; ++i) {
            int x = i;
            for (int j = i + 1; j < 10; ++j) {
                x = x * 10 + j;
                if (x >= low && x <= high) {
                    ans.push_back(x);
                }
            }
        }
        sort(ans.begin(), ans.end());
        return ans;
    }
};

Go

func sequentialDigits(low int, high int) (ans []int) {
	for i := 1; i < 9; i++ {
		x := i
		for j := i + 1; j < 10; j++ {
			x = x*10 + j
			if low <= x && x <= high {
				ans = append(ans, x)
			}
		}
	}
	sort.Ints(ans)
	return
}

TypeScript

function sequentialDigits(low: number, high: number): number[] {
    const ans: number[] = [];
    for (let i = 1; i < 9; ++i) {
        let x = i;
        for (let j = i + 1; j < 10; ++j) {
            x = x * 10 + j;
            if (x >= low && x <= high) {
                ans.push(x);
            }
        }
    }
    ans.sort((a, b) => a - b);
    return ans;
}