README_EN.md

comments	difficulty	edit_url	tags
true	Medium	https://github.com/doocs/leetcode/edit/main/solution/0700-0799/0779.K-th%20Symbol%20in%20Grammar/README_EN.md	Bit Manipulation Recursion Math

779. K-th Symbol in Grammar

中文文档

Description

We build a table of n rows (1-indexed). We start by writing 0 in the 1st row. Now in every subsequent row, we look at the previous row and replace each occurrence of 0 with 01, and each occurrence of 1 with 10.

• For example, for n = 3, the 1st row is 0, the 2nd row is 01, and the 3rd row is 0110.

Given two integer n and k, return the kth (1-indexed) symbol in the nth row of a table of n rows.

 

Example 1:

Input: n = 1, k = 1
Output: 0
Explanation: row 1: 0

Example 2:

Input: n = 2, k = 1
Output: 0
Explanation: 
row 1: 0
row 2: 01

Example 3:

Input: n = 2, k = 2
Output: 1
Explanation: 
row 1: 0
row 2: 01

 

Constraints:

• 1 <= n <= 30
• 1 <= k <= 2n - 1

Solutions

Solution 1

Python3

class Solution:
    def kthGrammar(self, n: int, k: int) -> int:
        if n == 1:
            return 0
        if k <= (1 << (n - 2)):
            return self.kthGrammar(n - 1, k)
        return self.kthGrammar(n - 1, k - (1 << (n - 2))) ^ 1

Java

class Solution {
    public int kthGrammar(int n, int k) {
        if (n == 1) {
            return 0;
        }
        if (k <= (1 << (n - 2))) {
            return kthGrammar(n - 1, k);
        }
        return kthGrammar(n - 1, k - (1 << (n - 2))) ^ 1;
    }
}

C++

class Solution {
public:
    int kthGrammar(int n, int k) {
        if (n == 1) return 0;
        if (k <= (1 << (n - 2))) return kthGrammar(n - 1, k);
        return kthGrammar(n - 1, k - (1 << (n - 2))) ^ 1;
    }
};

Go

func kthGrammar(n int, k int) int {
	if n == 1 {
		return 0
	}
	if k <= (1 << (n - 2)) {
		return kthGrammar(n-1, k)
	}
	return kthGrammar(n-1, k-(1<<(n-2))) ^ 1
}

Solution 2

Python3

class Solution:
    def kthGrammar(self, n: int, k: int) -> int:
        return (k - 1).bit_count() & 1

Java

class Solution {
    public int kthGrammar(int n, int k) {
        return Integer.bitCount(k - 1) & 1;
    }
}

C++

class Solution {
public:
    int kthGrammar(int n, int k) {
        return __builtin_popcount(k - 1) & 1;
    }
};

Go

func kthGrammar(n int, k int) int {
	return bits.OnesCount(uint(k-1)) & 1
}